Question

我有3个像这样的图像区域

<?php echo $row['thumbnail1']; ?>
<?php echo $row['thumbnail2']; ?>
<?php echo $row['thumbnail3']; ?>

如果只有一个exp thumbnail1有图像..

如何展示

以及如果图像1和图2只有数据......

请帮助如何显示php查询，如果只有1或2和3图像上传

这个css风格

 <div class="col-xs-12">
    <a href="#"><img src="#" class="w-full"></a>
   </div>

<!-- IF only 2 image available uploaded USE this -->                                                                        

 <div class="col-xs-4">
      <a href="#"><img src="#" class="w-full"></a>
 </div>
 <div class="col-xs-4">
      <a href="#"><img src="#" class="w-full"></a>
 </div>

<!-- IF only ALL/3 image available uploaded USE this -->        

<div class="col-xs-4">
     <a href="#"><img src="#" class="w-full"></a>
 </div>
 <div class="col-xs-4">
      <a href="#"><img src="#" class="w-full"></a>
 </div>  
 <div class="col-xs-4">
       <a href="#"><img src="#" class="w-full"></a>
 </div>
</div>

dsa sdas

Answer 1

用这个替换你的旧代码（有人编辑了所以我再次重新编写代码）：

<?php
if(isset($row['thumbnail1']))
{
?>
 <div class="col-xs-12">
    <a href="#"><img src="#" class="w-full"></a>
   </div>
<?php } ?>
<!-- IF only 2 image available uploaded USE this -->                                                                        
<?php
if(isset($row['thumbnail2']))
{
?>
 <div class="col-xs-4">
      <a href="#"><img src="#" class="w-full"></a>
 </div>
 <div class="col-xs-4">
      <a href="#"><img src="#" class="w-full"></a>
 </div>
<?php } ?>
<!-- IF only ALL/3 image available uploaded USE this -->        
<?php
if(isset($row['thumbnail3']))
{
?>
<div class="col-xs-4">
     <a href="#"><img src="#" class="w-full"></a>
 </div>
 <div class="col-xs-4">
      <a href="#"><img src="#" class="w-full"></a>
 </div>  
 <div class="col-xs-4">
       <a href="#"><img src="#" class="w-full"></a>
 </div>
<?php } ?>

如果您已经过测试，请告诉我更新。

显示php图像字段仅上载字段

1 个答案: