XSD验证错误：在xs：element中使用xs：any

Question

在我的XML架构中，我有以下定义：

<xs:element name="otherResultData">
    <xs:any processContents="lax" minOccurs="0" />
</xs:element>

这将给出验证错误：

  

'otherResultData'的内容必须匹配（注释？，（simpleType | complexType）？，（unique | key | keyref）*））。从以下问题开始发现问题：

有没有办法将其定义为：“这里可以有任何内容，但如果可以在此XSD中找到类型，那么它们是有效的”？

Answer 1

你需要像

这样的东西

CloseableHttpClient httpclient = HttpClients.createDefault();
ObjectMapper mapper = new ObjectMapper();
TestObj obj = new TestObj();
obj.setFile(IOUtils.toByteArray(new FileInputStream(new File("C:\\download.jpg"))));
obj.setMimetype("image/jpeg");
obj.setDescription("asd");
String jsonInString = mapper.writeValueAsString(obj);
HttpPost httpPost = new HttpPost("http://localhost:8080/url");
httpPost.setHeader("Authorization", "Bearer asdf");
httpPost.setHeader("Content-type", "application/json");
StringEntity se = new StringEntity(jsonInString);
httpPost.setEntity(se);
System.out.println(httpPost.toString());
CloseableHttpResponse response2 = httpclient.execute(httpPost);
try {
    System.out.println("!!!! " + jsonInString);
    System.out.println("!!!! " + se.toString());
    System.out.println("!!!! " + response2.getStatusLine());
    HttpEntity entity2 = response2.getEntity();
    EntityUtils.consume(entity2);
} finally {
    response2.close();
}