如何将子表值与父表行关联并插入子表值对应于php中的父表行

时间:2017-09-12 09:09:41

标签: php html

我有2个嵌套表。父表行包含子表。如果需要,两个表都可以通过添加按钮添加行。父表值插入数据库中的product_size表,子表值插入product_color表中。父表包含大小,子表包含该大小的项目的颜色和数量。我想在父表行中插入子表值(颜色和数量)。表示父第一行子表值应仅插入父第一行,而父表第二行中的子表值应插入父第二行。目前,我的代码获取父表的所有行中的所有子表值,并在第一行中插入数据库中,然后再次从父表的所有行中获取所有子表值,并在数据库的第二行中插入父表。请检查我的代码,并帮助我指出代码中的问题所在。 / PHP代码 /

if (isset($_POST['submit']))
{   
    $con=mysqli_connect("localhost", "root", "");
    mysqli_select_db($con,"login"); 

    for ($i=0; $i<count($_POST['size']); $i++){

        $size = $_POST['size'][$i];          

        $qry1="INSERT INTO product_size (product_size) VALUES ('$size')";

        $result1=mysqli_query($con,$qry1);
        $product_size_id = mysqli_insert_id($con);                    

        for ($j=0; $j<count($_POST['color']); $j++){

            $quantity = $_POST['dress_quantity'][$j];

            $color = $_POST['color'][$j];

            $qry2="INSERT INTO product_color (product_size_id, product_color, product_quantity) VALUES ('$product_size_id', '$color', '$quantity')";

            $result2=mysqli_query($con,$qry2); 
            if($result2)
            {
                echo '<script>alert("Record Added Successfully!")</script>';
                echo '<script>window.location="try.php"</script>';
            }
            else      
            {
                die("Error While Adding Stock! Please Try Again.");
            }
        }
    }
}

1 个答案:

答案 0 :(得分:0)

我在本地服务器上测试过。工作很好

    $con=mysqli_connect("localhost", "root", "");
    mysqli_select_db($con,"login"); 
  // $size1 = array("50", "60", "70");
  // $color1 =array("red", "blue", "green");
  // $quantity1 = array("10", "20", "30");
    for ($i=0; $i<count($_POST['size']); $i++){

        $size = $size1[$i];   

        $qry1="INSERT INTO product_size (product_size) VALUES ('$size')";
        $result1=mysqli_query($con,$qry1);
        var_dump($result1);
        echo "<br>";

        $product_size_id = mysqli_insert_id($con);                    

        for ($j=0; $j<count($size); $j++){

            $quantity = $_POST['dress_quantity'][$i];

            $color = $_POST['color'][$i];

            $qry2="INSERT INTO product_color (product_size_id, product_color, product_quantity) VALUES ('$product_size_id', '$color', '$quantity')";

            $result2=mysqli_query($con,$qry2); 
            if($result2)
            {
                echo '<script>alert("Record Added Successfully!")</script>';
             //   echo '<script>window.location="try.php"</script>';
            }
            else      
            {
                die("Error While Adding Stock! Please Try Again.");
            }
        }
    }
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