Question

我创建了一个捆绑包并且正在另一个项目中工作。我复制了src文件夹中的Bundle文件夹，复制了一些segurity参数，在config.yml中导入了服务资源，并在AppKernel.php中添加了包

新的LoginBundle \ LoginBundle（）

当我制作$ php bin/console doctrine:schema:validate时，它会返回此错误

PHP Fatal error:  Uncaught Symfony\Component\Debug\Exception\ClassNotFoundException: Attempted to load class "LoginBundle" from namespace "LoginBundle".
Did you forget a "use" statement for another namespace? in {project}\app\AppKernel.php:18
Stack trace:
#0 {project}\vendor\symfony\symfony\src\Symfony\Component\HttpKernel\Kernel.php(450): AppKernel->registerBundles()
#1 {project}\vendor\symfony\symfony\src\Symfony\Component\HttpKernel\Kernel.php(116): Symfony\Component\HttpKernel\Kernel->initializeBundles()
#2 {project}\vendor\symfony\symfony\src\Symfony\Bundle\FrameworkBundle\Console\Application.php(69): Symfony\Component\HttpKernel\Kernel->boot()
#3 {project}\vendor\symfony\symfony\src\Symfony\Component\Console\Application.php(125): Symfony\Bundle\FrameworkBundle\Console\Application->doRun(Object(Symfony\Component\Console\Input\ArgvInput), Object(Symfony\Component\Console\Output\ConsoleOutput))
#4 {project}\bin\console(27): Symfo in {project}\app\AppKernel.php on line 18

修改

AppKernel.php内容

<?php

use Symfony\Component\HttpKernel\Kernel;
use Symfony\Component\Config\Loader\LoaderInterface;

class AppKernel extends Kernel
{
    public function registerBundles()
    {
        $bundles = [
            new Symfony\Bundle\FrameworkBundle\FrameworkBundle(),
            new Symfony\Bundle\SecurityBundle\SecurityBundle(),
            new Symfony\Bundle\TwigBundle\TwigBundle(),
            new Symfony\Bundle\MonologBundle\MonologBundle(),
            new Symfony\Bundle\SwiftmailerBundle\SwiftmailerBundle(),
            new Doctrine\Bundle\DoctrineBundle\DoctrineBundle(),
            new Sensio\Bundle\FrameworkExtraBundle\SensioFrameworkExtraBundle(),
            new LoginBundle\LoginBundle(),
            new AppBundle\AppBundle(),
        ];

        if (in_array($this->getEnvironment(), ['dev', 'test'], true)) {
            $bundles[] = new Symfony\Bundle\DebugBundle\DebugBundle();
            $bundles[] = new Symfony\Bundle\WebProfilerBundle\WebProfilerBundle();
            $bundles[] = new Sensio\Bundle\DistributionBundle\SensioDistributionBundle();

            if ('dev' === $this->getEnvironment()) {
                $bundles[] = new Sensio\Bundle\GeneratorBundle\SensioGeneratorBundle();
                $bundles[] = new Symfony\Bundle\WebServerBundle\WebServerBundle();
            }
        }

        return $bundles;
    }

    public function getRootDir()
    {
        return __DIR__;
    }

    public function getCacheDir()
    {
        return dirname(__DIR__).'/var/cache/'.$this->getEnvironment();
    }

    public function getLogDir()
    {
        return dirname(__DIR__).'/var/logs';
    }

    public function registerContainerConfiguration(LoaderInterface $loader)
    {
        $loader->load($this->getRootDir().'/config/config_'.$this->getEnvironment().'.yml');
    }
}

这里是捆绑文件结构

这也是LoginBundle.php

namespace LoginBundle;

use Symfony\Component\HttpKernel\Bundle\Bundle;

class LoginBundle extends Bundle
{
}

Answer 1

我的解决方案是像

那样再次生成一个装配工

php composer.phar dump-autoload

希望它有助于某人

Answer 2

我认为在routing.yml中你必须添加

login:
    resource: "@LoginBundle/Controller/"
    type:     annotation
    prefix:   /

Symfony3错误添加新捆绑

2 个答案: