Question

lyricsForName功能不会打印任何内容。 shortNameFromName确实有效，我已经检查了第二个函数的错误。

func shortNameFromName(name : String) ->String{
    var shortName = ""

    let lowercaseNmae = name.lowercased()
    let vowelSet = CharacterSet(charactersIn: "aeiou")
    if let range = lowercaseNmae.rangeOfCharacter(from: vowelSet, options: String.CompareOptions.caseInsensitive)
    {
        shortName = name.substring(from: range.lowerBound)
    }

    return shortName
}

func lyricsForName(lyricsTemplate : String , fullName : String) ->String{
    let bananaFanaTemplate = ["<FULL_NAME>, <FULL_NAME>, Bo B<SHORT_NAME",
                            "Banana Fana Fo F<SHORT_NAME>",
                             "Me My Mo M<SHORT_NAME>",
                             "<FULL_NAME>"].joined(separator: "\n")
    let shortName = shortNameFromName(name: fullName)
    let lyrics = lyricsTemplate
        .replacingOccurrences(of: "<FULL_NAME>", with: fullName)
        .replacingOccurrences(of: "<SHORT_NAME>", with: shortName)

    print(lyricsForName(lyricsTemplate:bananaFanaTemplate , fullName: "vishnu"))

    return lyrics
}

第一个功能完美，但我猜第二个功能不能正常工作。我该怎么做才能让它发挥作用？

Answer 1

我现在在办公桌前，所以快速浏览一下你的代码。这现在有效（请注意bananaFanaTemplate中的拼写错误）：

func shortNameFromName(name : String) ->String{
     var shortName = ""

     let lowercaseNmae = name.lowercased()
     let vowelSet = CharacterSet(charactersIn: "aeiou")
     if let range = lowercaseNmae.rangeOfCharacter(from: vowelSet, options: String.CompareOptions.caseInsensitive) {
          shortName = name.substring(from: range.lowerBound)
     }

     return shortName
 }

 func lyricsForName(lyricsTemplate : String , fullName : String) -> String {

     let shortName = shortNameFromName(name: fullName)
     let lyrics = lyricsTemplate
          .replacingOccurrences(of: "<FULL_NAME>", with: fullName)
          .replacingOccurrences(of: "<SHORT_NAME>", with: shortName)

     print(lyrics)

     return lyrics
 }

 let bananaFanaTemplate : String = ["<FULL_NAME>, <FULL_NAME>, Bo B<SHORT_NAME>",
                               "Banana Fana Fo F<SHORT_NAME>",
                               "Me My Mo M<SHORT_NAME>",
                               "<FULL_NAME>"].joined(separator: "\n")

 print(lyricsForName(lyricsTemplate:bananaFanaTemplate , fullName: "vishnu"))

输出：

vishnu，vishnu，Bo Bishnu 香蕉Fana Fo Fishnu 我是我的Mishnu 毗

我认为你对功能范围问题很困惑。您在函数的实现中声明了常量bananaFanaTemplate，其中该参数应该已传入函数。同样，你从函数体内部调用了函数，除非它应该是一个递归函数，否则你通常不会这样做。

看看：https://developer.apple.com/library/content/documentation/Swift/Conceptual/Swift_Programming_Language/Functions.html

希望有所帮助。

lyricsForName函数不会打印任何内容

1 个答案: