Question

我在do-until块中使用以下内容循环，直到出现指定的Exchange Online迁移状态：

(Get-Migrationbatch -Identity $MigrationBatchName | Where {$_.Status -like "Completed" -or "CompletedWithErrors" -or "Corrupted" -or "Failed" -or "Stopped"})

但是，上述内容仍会返回状态为＆＃34;同步＆＃34;所以无论如何继续使用脚本。

我已尝试过-match，-eq但仍然相同。

我错过了什么？

Answer 1

你必须这样写：

(Get-Migrationbatch -Identity $MigrationBatchName | Where {($_.Status -like "Completed") -or ($_.Status -like "CompletedWithErrors") -or ($_.Status -like "Corrupted") -or ($_.Status -like "Failed") -or ($_.Status -like "Stopped")})

这是另一种方法：

$valuesToLookFor = @(
    'Completed',
    'CompletedWithErrors',
    'Corrupted',
    'Failed',
    'Stopped')

(Get-Migrationbatch -Identity $MigrationBatchName |
    Where-Object { $valuesToLookFor -contains $_.Status })

Answer 2

假设您不使用通配符，那么使用-in运算符会更简单：

(Get-Migrationbatch -Identity $MigrationBatchName | Where Status -in "Completed","CompletedWithErrors","Corrupted","Failed","Stopped")

Answer 3

另一个选择将过滤器数组转换为正则表达式字符串...

$filter_status = @("Completed", "CompletedWithErrors","Curropted","Failed", "Stopped")
(Get-Migrationbatch -Identity $MigrationBatchName | Where Status -Match ($filter_status -Join "|")

PowerShell Where-Object喜欢多个字符串值

3 个答案: