Question

我正在处理数据，我特别希望使用间隔对其进行分类。

List<string> columnOne = new List<string>(); foreach(DatagridViewColumn Column in DatagridView2.Column) { if (Column[0].Value.toString().Contains("lastName") { foreach(DatagridViewRow row in DatagridView2.Rows) { columnOne.add(row.Value.toString()); } } }命令非常有用，我可以使用，例如，

cut

以两个间隔对数据进行分类。处理是更复杂问题的一部分，最终需要将新数据分配给自动生成的区间。

最有效的方法是什么？因为尝试阅读data <- seq(1, 10) cut(data, 2) >> [1] (0.991,5.5] (0.991,5.5] (0.991,5.5] (0.991,5.5] (0.991,5.5] (5.5,10] (5.5,10] (5.5,10] (5.5,10] (5.5,10] Levels: (0.991,5.5] (5.5,10]进行分类似乎太脏了......

Answer 1

这是使用基础R的快速方法：

# Find intervals use original data
labs = levels(cut(data, 2))
labs_df = cbind(lower = as.numeric( sub("\\((.+),.*", "\\1", labs) ),
      upper = as.numeric( sub("[^,]*,([^]]*)\\]", "\\1", labs) ))

# Find intervals on new data
data_new = sample(1:10)
interval_idx = findInterval(data_new, labs_df[,1])
interval_idx

interval = labs[interval_idx]

data.frame(data_new, interval_idx, interval)

分类数据并分配新数据

1 个答案: