Question

我有一个包含两列的sql数据库 1. id和2. parent_id

我想选择parent_id = 1的所有id [让结果保存在X数组中]然后，选择X []中的parent_id所有的id [让结果保存在Y数组]然后...最后做7个等级我想要对所有级别求和并以变量名“number”得到该总和

我尝试了什么：

worker_processes  auto;

worker_rlimit_nofile 100000;

events {
    worker_connections  5000;
    multi_accept on;
    use epoll;
}


http {
    include       mime.types;
    default_type  application/octet-stream;

    sendfile        on;
    tcp_nopush     on;
    tcp_nodelay on;

    keepalive_timeout  10;
    keepalive_requests 1024;
    client_body_timeout 12;
    client_header_timeout 12;
    send_timeout 10;

    proxy_cache_path /tmp/mycache keys_zone=mycache:10m use_temp_path=off;
    limit_conn_zone $binary_remote_addr zone=addr:10m;
    server {
        listen       80;
        server_name  localhost;

    access_log off;

        error_page   500 502 503 504  /50x.html;
        location = /50x.html {
            root   html;
        }

    open_file_cache max=10000 inactive=30s;
    open_file_cache_valid    60s;
    open_file_cache_min_uses 5;
    open_file_cache_errors   on;

    client_body_buffer_size 16K;
    client_header_buffer_size 1k;
    client_max_body_size 8m;
    large_client_header_buffers 2 1k;

        location / {
        proxy_cache mycache;
        proxy_max_temp_file_size 1924m;
        slice              100m;
        proxy_cache_key    $host$uri$slice_range;
        proxy_set_header   Range $slice_range;
        proxy_http_version 1.1;
        proxy_ignore_headers X-Accel-Expires Expires Cache-Control Set-Cookie; 
        proxy_cache_valid  any 1d;
        limit_conn addr 5;
        proxy_pass   http://domain2.com/;
        secure_link $arg_md5,$arg_expires;
        secure_link_md5 "secret$secure_link_expires$uri";

        if ($secure_link = "") { return 403; }
                if ($secure_link = "0") { return 410; }
        }

    }

}

然后再次

$sql = "SELECT count(id) as leadersearch FROM `$database`.`$mem` where parent_id = ".$parent[id];
$result = mysqli_query($con, $sql);
$lv1 = mysqli_fetch_array($result);

依此类推....它可能会给我所需的结果，但代码太多...... 我希望通过使用循环或其他东西来缩短代码。

Answer 1

您的第一个查询获取计数（id），然后第二个查询使用它来获取结果。你的要求似乎有许多缺陷。

但是，对于您的问题，您可以使用如下的

子查询

$sql = "SELECT count(id) as leadersearch 
 FROM `$database`.`$mem` 
 WHERE parent_id in (
       SELECT id FROM `$database`.`$mem` where parent_id = ".$parent['id']."
  )";
$result = mysqli_query($con, $sql);
$lv2 = mysqli_fetch_array($result);

如果您有多个级别嵌套并且想要搜索这样的记录，那么您可以考虑函数：

function getLeader($parent_id){
    $results = [];
    $sql = "SELECT id as leadersearch FROM `$database`.`$mem` where parent_id in (".$parent_id.")";
    $result = mysqli_query($con, $sql);

    foreach($row = mysqli_fetch_array($result)){
        $results[] = $row['id'];
    }

    return $results;
}

$leaders = [];
$ids = getLeader($parent['id']);
foreach($ids as $id){
    $leaders[$id] = getLeader($id);
}

在sql中获取所需的结果

1 个答案: