Question

我遇到一些我无法弄清楚的功课问题，如果有人能指出我正确的方向，我会非常感激。我的哨兵价值根本不起作用，我无法弄清楚它是否有效。我的平均值数组也是打印出来的内存位置，而不是值。这是我到目前为止的代码

 public class DistanceFromAverage
{//Global Declaration Section

 public static void main(String args[])
 {//Declaration Section
 double[] Numbers;
 double[] Average;


 //Input Section

 Numbers = array_numbers();

 //Processing Section

Average = distance_average(Numbers);

 //Output Section

 display_array(Numbers, Average);


 }//end




  public static double[] array_numbers()
{
   double[] tmp;
   tmp = new double[20];
   double[] sentinel = {99999}; 
   Scanner input = new Scanner(System.in);
   int count = 0;

 try
   {
      for (int i = 0; i < tmp.length; i++)
      {
         System.out.println("Please enter number");
         tmp[i] = input.nextDouble();


      }
   }
 catch(InputMismatchException exception)
   {
      System.out.println("A number must be entered");
      System.exit(0);
   }

   return tmp; 
}//end array

public static double[] distance_average(double[] Numbers) {

     double sum = 0.0;


        for (int i=0; i < Numbers.length; i++) 

          sum = sum + Numbers[i]; 
          double average = sum / Numbers.length;


  return new double[] {average};
} // determine average



public static void display_array(double[] Numbers, double[] Average)
{

   for (int i = 0; i < Numbers.length; i++){

   System.out.println("The numbers in the array are: " + Numbers[i] + "and the average is" + Average);
   }
}//end display_array







}//end class

Answer 1

关于打印为内存位置的平均值，您的显示功能接受Average作为数组而不是简单的double。这将在Array类上调用toString（）。由于平均值只是一个数字，因此在“System.out.println”语句中使用Average[0]或在显示方法中接受类型为double的简单平均值，如下所示：

public static void display_array(double[] Numbers, double Average)

并更改

的签名

public static double[] distance_average(double[] Numbers) {

到

public static double distance_average(double[] Numbers) {

数组打印作为内存位置和标记值不起作用

1 个答案: