反序列化JSON返回空数据

时间:2017-09-19 07:18:29

标签: json datacontractjsonserializer

我使用api url来获取json响应

http://localhost/WaWebService/Json/NodeDetail/Demo/SCADA_NODE_DEMO

使用Postman软件验证是否有响应

{
    "Result": {
        "Ret": 0
    },
    "Node": {
        "ProjectId": 1,
        "NodeId": 1,
        "NodeName": "SCADA_NODE_DEMO",
        "Description": "",
        "Address": "SALMAN-MUSHTAQ",
        "Port1": 0,
        "Port2": 0,
        "Timeout": 0
    }
}

之后我上课

class Result
    {
        public int Ret { get; set; }
    }

    public class Node
    {
        public int ProjectId { get; set; }
        public int NodeId { get; set; }
        public string NodeName { get; set; }
        public string Description { get; set; }
        public string Address { get; set; }
        public int Port1 { get; set; }
        public int Port2 { get; set; }
        public int Timeout { get; set; }
    }

现在,我使用DataContractJsonSerializer

对json对象进行反序列化
var client = new WebClient { Credentials = new NetworkCredential("username", "password") };


                string json = client.DownloadString(url);
                using(var ms = new MemoryStream (Encoding.Unicode.GetBytes(json)))
                {
                    DataContractJsonSerializer deserializer = new DataContractJsonSerializer(typeof(Node));
                    Node nObj = (Node)deserializer.ReadObject(ms);
                    Console.WriteLine("Node name: " + nObj.NodeName);
                }

它在控制台上什么都没有。请帮忙解决这个问题。提前谢谢。

1 个答案:

答案 0 :(得分:1)

您应该创建与响应json

具有相同结构的类
class JsonResponse
{
    public Result Result { get; set; }
    public Node Node { get; set; }
}

class Result
{
    public int Ret { get; set; }
}

public class Node
{
    public int ProjectId { get; set; }
    public int NodeId { get; set; }
    public string NodeName { get; set; }
    public string Description { get; set; }
    public string Address { get; set; }
    public int Port1 { get; set; }
    public int Port2 { get; set; }
    public int Timeout { get; set; }
}

然后像这样反序列化json

DataContractJsonSerializer deserializer = new DataContractJsonSerializer(typeof(JsonResponse)); 
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