我有一组consts,然后我动态创建一个等于其中一个consts名称的变量。我需要调用那个const,我知道我可以使用if else语句,但我想知道是否有更好的方法谢谢!
public const int LifeBand1Standard = 78;
public const int LifeBand1Multi = 61;
public const int LifeBand2Standard = 71;
public const int LifeBand2Multi = 56;
public const int LifeBand3Standard = 62;
public const int LifeBand3Multi = 48;
public const int LifeBand4Standard = 56;
public const int LifeBand4Multi = 44;
public const int LifeBand5Standard = 45;
public const int LifeBand5Multi = 35;
// Band discounts/loads for trauma cover
public const int TraumaBand1Standard = 140;
public const int TraumaBand1Multi = 126;
public const int TraumaBand2Standard = 135;
public const int TraumaBand2Multi = 121;
public const int TraumaBand3Standard = 121;
public const int TraumaBand3Multi = 109;
public const int TraumaBand4Standard = 110;
public const int TraumaBand4Multi = 99;
public const int TraumaBand5Standard = 100;
public const int TraumaBand5Multi = 90;
protected float GetPercentageFromBand(int band)
{
var constantName = "Life";
if (IsTraumaCover == true)
{
constantName = "Trauma";
}
constantName += "Band" + band;
if (IsMultiLife == true)
{
constantName += "Multi";
}
else
{
constantName += "Standard";
}
// Constant should look something like LifeBand3Standard and will return the value of the const LifeBand3Standard
BandPercentage = InsuranceBandFetcher.constantName;
}
答案 0 :(得分:2)
使用enum
加上Dictionary
之类的内容(只是示例代码)
public enum MyConstant
{
LifeBand1Standard = 78,
LifeBand1Multi = 61,
LifeBand2Standard = 71,
LifeBand2Multi = 56,
LifeBand3Standard = 62,
LifeBand3Multi = 48
}
将数据保存在字典中
Dictionary<string, MyConstant> dict = new Dictionary<string, MyConstant>
{
{ "TraumaCover ", MyConstant.LifeBand3Multi},
{ "MultiLife ", MyConstant.LifeBand2Standard}
};
Console.WriteLine(dict["MultiLife "]);
根据您的评论,另一个示例代码。您可以将Enum.Parse()
用于此目的,例如
namespace Test
{
class Program
{
static void Main(string[] args)
{
string key = PrepareConstant(1, false);
MyConstant val = (MyConstant)Enum.Parse(typeof(MyConstant), key, true);
Dictionary<string, MyConstant> dict = new Dictionary<string, MyConstant>
{
{ key, val},
};
Console.WriteLine(dict[key]); // output: LifeBand1Standard
Console.ReadKey();
}
static string PrepareConstant(int band, bool isMultiLife)
{
var constantName = "Life";
constantName += "Band" + band;
constantName += (isMultiLife) ? "Multi" : "Standard";
return constantName;
}
}
public enum MyConstant
{
LifeBand1Standard = 78,
LifeBand1Multi = 61,
LifeBand2Standard = 71,
LifeBand3Standard = 62,
TrumaBand2Multi = 56,
TrumaBand3Multi = 48
}
}
答案 1 :(得分:0)
使用字典而不是魔术字符串(尤其是以编程方式创建的字符串)。
我不了解您的业务领域,因此我的枚举名称/值可能完全不同,但这就是我如何解决问题:
public enum Cover
{
Life,
Trauma
}
public enum MultiLife
{
Multi,
Standard
}
public readonly Dictionary<Tuple<Cover, int, MultiLife>, int> Values
= new Dictionary<System.Tuple<UserQuery.Cover, int, UserQuery.MultiLife>, int>
{
[Tuple.Create(Cover.Life, 1, MultiLife.Standard)] = 78,
[Tuple.Create(Cover.Life, 1, MultiLife.Multi)] = 61,
[Tuple.Create(Cover.Life, 2, MultiLife.Standard)] = 71,
// [...]
};
然后用法是:
var bandPercentage
= Values[Tuple.Create(IsTraumaCover ? Cover.Trauma : Cover.Life,
band,
IsMultiLife ? MultiLife.Multi : MultiLife.Standard)];
答案 2 :(得分:0)
如果没有反思,你所要做的就是不可能。即使有反射,这也不是推荐的设计。
您似乎想要的是一个从三个值映射的函数: 1.多或标准(布尔或枚举)。 2.生命或创伤(布尔或枚举)。 3. Number(int)(或byte或custom struct) 并返回一些数字(百分比?)。
enum BandKind {
Multi,
Standard,
}
enum BandType {
Life,
Trauma
}
int GetBandValue(BandKind kind, BandType type, int num) {
/// impl here
}
好的,那么如何实现GetBandValue?您可以使用嵌套的switch语句并返回文字值,这将是一个选项,但嵌套的开关最终会变得有点难看。您可以使用值创建一个多维数组并将其索引。
int[][][] BandData = {{{78, 61},{71, 56},...}}}; // build this array with your real values.
然后您的实施可以是:
int GetBandValue(BandKind kind, BandType type, int num) {
return BandData[(int)kind][(int)type][num];
}