Question

我想右键单击一个链接并选择上下文菜单中的第一个选项。

我试过以下五种方法没有用。所有方法都是点击正常方式的链接，但没有发生上下文点击。

有人可以说明这有什么不对吗？

我正在使用... selenium-3.4.0，FF 53，Windows 7

的环境

        package WebDriverAdvancedPrograms;


        import java.awt.AWTException;
        import java.awt.Robot;
        import java.awt.event.KeyEvent;
        import java.util.concurrent.TimeUnit;

        import org.openqa.selenium.*;
        import org.openqa.selenium.firefox.FirefoxDriver;
        import org.openqa.selenium.interactions.Action;
        import org.openqa.selenium.interactions.Actions;

        public class RightClick {

            public static void main(String[] args) throws InterruptedException, AWTException {
                System.setProperty("webdriver.gecko.driver", "G:\\Selenium\\geckodriver-v0.16.0-win64\\geckodriver.exe");
                WebDriver driver = new FirefoxDriver();
                driver.get("http://facebook.com");
                driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);

                WebElement element=driver.findElement(By.linkText("Forgotten account?"));


    //      // Method 1 - NOT WORKING
    //      Actions builder = new Actions(driver);
    //      Action mouseOverHome = builder
    //              .moveToElement(element)
    //              .contextClick(element)
    //              .sendKeys(Keys.DOWN)
    //              .sendKeys(Keys.ENTER)
    //              .build();
    //      mouseOverHome.perform();

    // Method 2 - NOT WORKING
    //      Actions builder = new Actions(driver);
    //      Action mouseOverHome = builder
    //              .moveToElement(element)
    //              .contextClick(element)
    //              .sendKeys(Keys.ARROW_DOWN)
    //              .sendKeys(Keys.RETURN)
    //              .build();
    //      mouseOverHome.perform();

    // Method 3 - NOT WORKING
    //      Actions builder = new Actions(driver);
    //      Action mouseOverHome = builder
    //              .contextClick(element)
    //              .sendKeys(Keys.ARROW_DOWN)
    //              .sendKeys(Keys.RETURN)
    //              .build();
    //      mouseOverHome.perform();

    // Method 4 - NOT WORKING
    //      Actions builder = new Actions(driver);
    //      Action mouseOverHome = builder
    //              .contextClick(element)
    //              .sendKeys(Keys.ARROW_DOWN)
    //              .sendKeys(Keys.ARROW_UP)
    //              .sendKeys(Keys.RETURN)
    //              .build();
    //      mouseOverHome.perform();


    //      // Method 5 - NOT WORKING
            Actions action= new Actions(driver);
            action.contextClick(element).sendKeys(Keys.ARROW_DOWN).sendKeys(Keys.RETURN).build().perform();



   // Method 6 - Partially WORKING
    Point p = element.getLocation();
    int x = p.getX();
    int y = p.getY();

    Robot r=new Robot();
    r.mouseMove(x, y);
    r.mousePress(InputEvent.BUTTON3_MASK);
    r.mouseRelease(InputEvent.BUTTON3_MASK);
    r.keyPress(KeyEvent.VK_DOWN);
    r.keyRelease(KeyEvent.VK_DOWN);

    r.keyPress(KeyEvent.VK_ENTER);
    r.keyRelease(KeyEvent.VK_ENTER);

   //Method 7 - WORKING
    Robot r=new Robot();
    r.mouseMove(1000, 145);
    r.mousePress(InputEvent.BUTTON3_MASK);
    r.mouseRelease(InputEvent.BUTTON3_MASK);
    r.keyPress(KeyEvent.VK_DOWN);
    r.keyRelease(KeyEvent.VK_DOWN);

    r.keyPress(KeyEvent.VK_ENTER);
    r.keyRelease(KeyEvent.VK_ENTER);


        }
    }

方法6部分工作意味着......上下文点击发生在屏幕上但不在元素上。

在方法7中，我手动输入x，y定位其工作...

方法6无法工作的原因是x，y从getLocation方法获取与浏览器有关，但机器人类与屏幕有关..

我的问题是如何获得与屏幕相关的元素的确切位置

由于 Ravi M

Answer 1

请尝试，

Actions builder = new Actions(driver);
builder.ContextClick(element).Build().Perform();

或者请尝试将RETURN更改为ENTER，如下所示，

Actions action= new Actions(driver);
action.contextClick(element).sendKeys(Keys.ARROW_DOWN).sendKeys(Keys.ENTER).build().perform();

Answer 2

使用它：

Actions right_action = new Actions(chromeDriver);  
right_action.ContextClick(element_name).SendKeys(Keys.ArrowDown).SendKeys(Keys.Enter).Build().Perform();

右键单击在selenium Web驱动程序

2 个答案: