循环不打印正确的输出

时间:2017-09-24 03:04:11

标签: python

x = int(input('Enter x: '))
y = int(input('Enter y: '))

product = 0
## 50 in border
border = str('-------------------------------------------------------')
print(border)
print('%15s' % 'x', '%15s' % 'y', '%23s' % 'product')
print(border)

if y < x:
    temp = x
    x = y
    y = temp
xTwo = x
yTwo = y

productTwo = x*y

while not x <= 0:

    if x % 2 == 0:
        x = x / 2
        y = y*2

    else: 
        x = x - 1
        product = product + y

    print('%15d' % x, '%15d' % y, '%23d' % int(product))

else:
    print(border)
    print(xTwo, '*', yTwo, '=', productTwo)

**以下是它的产生。在循环中,我希望第一个数字行读取&#39; 12 14 0&#39;但是我不确定我需要在哪里放置打印线,或者我是否可以稍微改变循环以产生结果****

Enter x: 12
Enter y: 14
-------------------------------------------------------
          x               y                 product
-------------------------------------------------------
          6              28                     168
          3              56                     168
          2              56                     224
          1             112                     224
          0             112                     336
-------------------------------------------------------
12 * 14 = 168

1 个答案:

答案 0 :(得分:0)

问题在于print语句的位置。您需要将它放在while循环的第一行。如果不这样做,则x%2 = 0条件变为真,x值改变。

x = int(input('Enter x: '))
y = int(input('Enter y: '))

product = 0
## 50 in border
border = str('-------------------------------------------------------')
print(border)
print('%15s' % 'x', '%15s' % 'y', '%23s' % 'product')
print(border)

if y < x:
    temp = x
    x = y
    y = temp
xTwo = x
yTwo = y

productTwo = x*y

while not x <= 0:
    print('%15d' % x, '%15d' % y, '%23d' % int(product))

    if x % 2 == 0:
        x = x / 2
        y = y*2

    else: 
        x = x - 1
        product = product + y


else:
    print(border)
    print(xTwo, '*', yTwo, '=', productTwo)
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