wpf STA线程和

Question

当我尝试执行My Lines of Code

时

//使用Staements

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading;
using System.Threading.Tasks;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
using TwitchLib;
using TwitchLib.Events.Client;
using TwitchLib.Models.Client;

//我的代码行

void PostMessage(string UserName,string UserType, bool isSub, string Message)
{
    StackPanel SP = new StackPanel();
    SP.Orientation = Orientation.Horizontal;
    TextBlock DT = new TextBlock();
    DT.Text = DateTime.Now.ToShortTimeString();
    SP.Children.Add(DT);
    TextBlock Caster = new TextBlock();
    TextBlock Type = new TextBlock();
    switch (UserType)
    {
        case "Broadcaster":
            Caster.Text = " CASTER ";
            SP.Children.Add(Caster);
            Type.Text = " MOD ";
            SP.Children.Add(Type);
            break;
        case "Moderator":
            Type.Text = " MOD ";
            SP.Children.Add(Type);
            break;
        case "GlobalModerator":
            Type.Text = " GMOD ";
            SP.Children.Add(Type);
            break;
        case "Staff":
            Type.Text = " STAFF ";
            SP.Children.Add(Type);
            break;
        case "Admin":
            Type.Text = " ADMIN ";
            SP.Children.Add(Type);
            break;
        default:
            break;
    }
    if (isSub == true)
    {
        TextBlock Sub = new TextBlock();
        Sub.Text = " SUB ";
        SP.Children.Add(Sub);
    }
    TextBlock UName = new TextBlock();
    SP.Children.Add(UName);
    UName.Text = " " + UserName + ": ";
    TextBlock Mess = new TextBlock() ;
    Mess.Text = Message;
    SP.Children.Add(Mess);
    //ChatWindow.Text += DT + pretag + UserName + Message + Environment.NewLine;
    ChatWindow.Dispatcher.Invoke(new Action(() => ChatWindow.Items.Add(SP)));
}

我拉这个异常“调用线程必须是STA，因为许多UI组件都需要这个。”

如果我试试这个

void PostMessage(string UserName,string UserType, bool isSub, string Message)
{
Thread thread = new Thread(() => {
    //Same inside Code
});
thread.SetApartmentState(ApartmentState.STA);
thread.Start();
}

我拉出异常'调用线程无法访问此对象，因为另一个线程拥有它。'

基本上它把对待就好像调用从未发生过一样 有些人可以给我一些建议。我是使用WPF的新手。