d3获取树

Question

我尽量保持尽可能短的时间：

在代码片段中，我有一个代表树的Json。在d3的帮助下，我尝试将根的所有子节点都作为数组。为此我使用函数＆＃34;节点＆＃34;。

问题是我的孩子的钥匙被称为＆＃34; _children＆＃34;而不是＆＃34;孩子＆＃34;。我试图找到一个很好的解决方案来告诉节点功能检查＆＃34; children＆＃34;而不是＆＃34;孩子＆＃34;。如果我删除＆＃34; ＆＃34;所有儿童钥匙都有效。

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var json = {"_name":"root","_children":[{"_name":"Application","_children":[{"_name":"Application Heap","_children":[],"_color":"#0000ff", "MEMORY":20},{"_name":"Other","_children":[],"_color":"#000055","MEMORY":30},{"_name":"Statement Heap","_children":[],"_color":"","MEMORY":40}]}]};

console.log(json);

// tell d3 that my children key is "_children"
var treemap = d3.layout.treemap()
    .children(function(d) { return d._children; })
    .value(function(d) { return d.MEMORY; });

// With this line I try to get all child nodes of the root element
var nodes = treemap.nodes(json)
    .filter(function(d) {return !d._children; });
    
console.log(json);  // d3 sets the value and everything else correct
console.log(nodes); // for some reason I get an empty array

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<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.11/d3.min.js"></script>

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Answer 1

一种可能的解决方案（但不是我想要的解决方案）是首先将字段重命名为：

var renameKeys=function(obj){
    if(obj._children){
        obj.children=obj._children;
        delete obj._children;
        obj.children.forEach(renameKeys);
    }
return obj;
};