Question

给定项目结构：

rootProject
  aggregatingSubProject
    subA
    subB
  subC

如何为package及其所有聚合项目运行aggregatingSubProject任务，而不是手动指定它们？

到目前为止，在subA中执行subB时，我只能构建package和rootProject - 无论我将.aggregate(subA, subB)放在aggregatingProject中} build.sbt。

我需要rootProject来定义构建的常用设置，我想在一个构建中构建多个项目（一些聚合其他项目，如aggregatingSubProject）。

编辑：我需要在没有指定根build.sbt中的所有子项目的情况下执行此操作。我想在aggregatingSubProject / build.sbt中定义subA和subB。

使用sbt 0.13.16。

Answer 1

在build.sbt：

中给出了这一点

val rootProject = project in file(".")
val aggregatingSubProject = project
val subC = project

，这在aggregatingSubProject/build.sbt：

中

aggregateProjects(subA, subB)

val subA = project
val subB = project

您可以运行aggregatingSubProject/package并获取：

> aggregatingSubProject/package
[info] Updating {file:/s/t-subaggregate/}subB...
[info] Updating {file:/s/t-subaggregate/}aggregatingSubProject...
[info] Updating {file:/s/t-subaggregate/}subA...
[info] Done updating.
[info] Packaging /s/t-subaggregate/aggregatingSubProject/subA/target/scala-2.12/suba_2.12-0.1-SNAPSHOT.jar ...
[info] Done updating.
[info] Done packaging.
[info] Packaging /s/t-subaggregate/aggregatingSubProject/subB/target/scala-2.12/subb_2.12-0.1-SNAPSHOT.jar ...
[info] Done packaging.
[info] Done updating.
[info] Packaging /s/t-subaggregate/aggregatingSubProject/target/scala-2.12/aggregatingsubproject_2.12-0.1-SNAPSHOT.jar ...
[info] Done packaging.

SBT汇总子项目

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