Question

我有一个单词字典，其频率如下。

Double legacyRow = row.getCell(col).getNumericCellValue();
String legacyRowStr = legacyRow.toString();
if(legacyRowStr.contains(".0")){
    legacyRowStr = legacyRowStr.substring(0, legacyRowStr.length()-2);
}

我有一组字符串（删除标点符号），如下所示。

mydictionary = {'yummy tim tam':3, 'milk':2, 'chocolates':5, 'biscuit pudding':3, 'sugar':2}

在上面的字符串中，我需要通过引用字典输出“饼干布丁”，“美味的蒂姆塔姆”和“牛奶”。不是糖，因为它的原料是在绳子里。

但是，我目前使用的代码也输出了糖。

recipes_book = "For todays lesson we will show you how to make biscuit pudding using 
yummy tim tam milk and rawsugar"

如何避免使用这样的子字符串，只考虑一个完整的标记，如“牛奶”。请帮帮我。

Answer 1

使用字边界＆＃39; \ b＆＃39;。简单来说就是

recipes_book = "For todays lesson we will show you how to make biscuit pudding using 
yummy tim tam milk and rawsugar"

>>> re.findall(r'(?is)(\bchocolates\b|\bbiscuit pudding\b|\bsugar\b|\byummy tim tam\b|\bmilk\b)',recipes_book)
['biscuit pudding', 'yummy tim tam', 'milk']

Answer 2

您可以使用正则表达式字边界更新代码：

mydictionary = {'yummy tim tam':3, 'milk':2, 'chocolates':5, 'biscuit pudding':3, 'sugar':2}
recipes_book = "For today's lesson we will show you how to make biscuit pudding using yummy tim tam milk and rawsugar"
searcher = re.compile(r'{}'.format("|".join(map(lambda x: r'\b{}\b'.format(x), mydictionary.keys()))), flags=re.I | re.S)

for match in searcher.findall(recipes_book):
    print(match)

输出：

biscuit pudding
yummy tim tam
milk

Answer 3

使用re.escape的另一种方法。有关re.escape here !!!

的更多信息

import re

mydictionary = {'yummy tim tam':3, 'milk':2, 'chocolates':5, 'biscuit pudding':3, 'sugar':2}
recipes_book = "For today's lesson we will show you how to make biscuit pudding using yummy tim tam milk and rawsugar"

val_list = []

for i in mydictionary.keys():
    tmp_list = []
    regex_tmp = r'\b'+re.escape(str(i))+r'\b'
    tmp_list = re.findall(regex_tmp,recipes_book)
    val_list.extend(tmp_list)

print val_list

<强>输出：

"C:\Program Files (x86)\Python27\python.exe" C:/Users/punddin/PycharmProjects/demo/demo.py
['yummy tim tam', 'biscuit pudding', 'milk']

在python中删除子串时识别字符串

3 个答案: