Question

我有两个不同的表tbl_address和tbl_support。我想从address和postcod选择tbl_support，insert e到tbl_address，然后在update address_id中选择tbl_support id上次插入tbl_address = id, address, postcode, country. tbl_support = id, address_id ,name, address,postcode,的{1}}。我该如何撰写查询。

{{1}}

Answer 1

如果地址表autoincrement中的列id字段尝试：

   insert into tbl_address select address, postcode from tbl_support;

然后，如果地址和邮政编码是唯一的设置，您可以更新tbl_support。

 update tbl_support s set s.address_id=(select id from tbl_address a where 
 a.address=s.address and a.postcode = s.postcode)

Answer 2

您需要执行两个单独的查询。首先在tbl_address表中插入所有tbl_support记录。然后你需要执行第二个查询，你可以通过匹配的tbl_address地址，邮政编码和tbl_support地址，邮政编码等来更新address_id。

INSERT INTO tbl_address ( 
      address, 
      postcode) 
SELECT address, 
       postcode 
FROM `tbl_support`;

UPDATE `tbl_support` SET address_id = (SELECT id FROM `tbl_address` 
WHERE  tbl_support.address= tbl_address.address 
AND tbl_support.postcode= tbl_address.postcode)

Mysql从一个表中选择记录并添加到表2中，将最后插入的ID更新到table1中

2 个答案: