Question

我有这个字符串，我需要删除与值匹配的AND子句。例如：RHID = '540' AND SEQ LIKE '%44%' AND NR_DOCUMENTO LIKE '%999%'

如果值为＆＃39;％999％＆＃39;我需要删除AND NR_DOCUMENTO LIKE '%999%'。如果值为＆＃39;％44％＆＃39;

，我需要删除AND SEQ LIKE '%44%'

注意：AND查询部分是动态的，可能有不同的东西，因此更像是找到值并向后移除到AND

Answer 1

你可以试试这个：

AND(?=(?:(?!AND).)*'%(?:44|999)%').*?LIKE\s+'%.*?%'

Regex Demo

const regex = /AND(?=(?:(?!AND).)*'%(?:44|999)%').*?LIKE\s+'%.*?%'/gim;
const str = `'540' AND sEQ LIKE '%44%' AND NR_DOCUMENTO LIKE '%45%' AND bla bla bla LIKE '%999%'`;
const result = str.replace(regex,``);
console.log(result);

Answer 2

这应该可以解决问题：

var string = "RHID = '540' AND SEQ LIKE '%44%' AND NR_DOCUMENTO LIKE '%999%'";

function replaceIt (valueSEQ, valueLIKE) {
  return string.replace(" AND SEQ LIKE '%" + valueSEQ +"%'", "")
               .replace(" AND NR_DOCUMENTO LIKE '%" + valueLIKE + "%'", "");
}

console.log( replaceIt(44, 999) );

＆＃13;

    var string = "RHID = '540' AND SEQ LIKE '%44%' AND NR_DOCUMENTO LIKE '%999%'";
    
function replaceIt (valueSEQ, valueLIKE) {
    return string.replace(" AND SEQ LIKE '%" + valueSEQ +"%'", "")
                 .replace(" AND NR_DOCUMENTO LIKE '%" + valueLIKE + "%'", "");
}
    
console.log( replaceIt(44, 999) );

＆＃13;

Javascript替换匹配值

2 个答案: