Question

我有一个Spring boot Web应用程序，我使用 java -jar application.jar 运行。我需要从代码中动态获取jar父文件夹路径。我怎么能做到这一点？

我已经尝试了this，但没有成功。

Answer 1

嗯，对我有用的是对this answer的改编。代码是：

如果你使用java -jar运行myapp.jar，dirtyPath就会关闭对此：jar：file：/ D：/arquivos/repositorio/myapp/trunk/target/myapp-1.0.3-RELEASE.jar！/ BOOT-INF / classes！/ br / com / cancastilho / service。或者，如果您从Spring Tools Suit运行，可能是这样的：文件：/ d：/ arquivos / repositorio / MyApp的/中继/目标/类/ BR / COM / cancastilho /服务

public String getParentDirectoryFromJar() {
    String dirtyPath = getClass().getResource("").toString();
    String jarPath = dirtyPath.replaceAll("^.*file:/", ""); //removes file:/ and everything before it
    jarPath = jarPath.replaceAll("jar!.*", "jar"); //removes everything after .jar, if .jar exists in dirtyPath
    jarPath = jarPath.replaceAll("%20", " "); //necessary if path has spaces within
    if (!jarPath.endsWith(".jar")) { // this is needed if you plan to run the app using Spring Tools Suit play button. 
        jarPath = jarPath.replaceAll("/classes/.*", "/classes/");
    }
    String directoryPath = Paths.get(jarPath).getParent().toString(); //Paths - from java 8
    return directoryPath;
}

编辑：

实际上，如果你使用春季启动，你可以像这样使用ApplicationHome类：

ApplicationHome home = new ApplicationHome(MyMainSpringBootApplication.class);
home.getDir();    // returns the folder where the jar is. This is what I wanted.
home.getSource(); // returns the jar absolute path.

Answer 2

    File file = new File(".");
    logger.debug(file.getAbsolutePath());

这对我来说是运行我的jar运行的路径，我希望这是你所期待的。

Answer 3

尝试此代码

public static String getParentRealPath(URI uri) throws URISyntaxException {
    if (!"jar".equals(uri.getScheme()))
        return new File(uri).getParent();
    do {
        uri = new URI(uri.getSchemeSpecificPart());
    } while ("jar".equals(uri.getScheme()));
    File file = new File(uri);
    do {
        while (!file.getName().endsWith(".jar!"))
            file = file.getParentFile();
        String path = file.toURI().toString();
        uri = new URI(path.substring(0, path.length() - 1));
        file = new File(uri);
    } while (!file.exists());
    return file.getParent();
}

URI uri = clazz.getProtectionDomain().getCodeSource().getLocation().toURI();
System.out.println(getParentRealPath(uri));

如何动态获取spring boot应用程序jar父文件夹路径？

3 个答案: