Question

我正在尝试将表单中的数据添加到数据库中。但是，当我单击“提交”按钮时，它会显示以下错误：

Notice: Array to string conversion in C:\xampp\htdocs\stock\php_action\createAppointment.php on line 16

Notice: Array to string conversion in C:\xampp\htdocs\stock\php_action\createAppointment.php on line 16
{"success":true,"messages":"Successfully Added"}

我已经搜索并登陆了这个网站。它告诉我使用implode，但我不知道放在哪里，当我查看函数时，它将数组回显到字符串中，但我想将数据添加到数据库而不是回显它。

以下是第16行事项的代码：

<?php   
require_once 'core.php';

$valid['success'] = array('success' => false, 'messages' => array(), 'appointment_id' => '');
// print_r($valid);
if($_POST) {    

  $appointmentDate          = date('Y-m-d', strtotime($_POST['appointmentDate']));  
  $patientName              = $_POST['patientName'];
  $physicianName            = $_POST['physicianName'];
  $description              = $_POST['description'];



    $sql = "INSERT INTO appointment (appointment_date, patient_name, physician_name, description) VALUES ('$appointmentDate', '$patientName', '$physicianName', '$description')";
    }
    if($connect->query($sql) === TRUE) {
                    $valid['success'] = true;
                    $valid['messages'] = "Successfully Added";  
                } else {
                    $valid['success'] = false;
                    $valid['messages'] = "Error while adding the members";
                }

// /if $_POST
// echo json_encode($valid);
    $connect->close();

    echo json_encode($valid);

// /if $_POST

第16行就是这一行：

 $sql = "INSERT INTO appointment (appointment_date, patient_name, physician_name, description) VALUES ('$appointmentDate', '$patientName', '$physicianName', '$description')";

编辑：

我已经检查了我的数据库并且它增加了值（虽然我添加了空数据，除了描述中有's'的顶部数据）但医生姓名和患者姓名是数组。

这是我的医生姓名代码（与患者姓名相同）：

<?php
    $physicianSql = "SELECT * FROM physician WHERE physician_active = 1 AND physician_status = 1";
    $physicianData = $connect->query($physicianSql);

    while($row = $physicianData->fetch_array()) {                                           
        $selected = "";
        if($row['physician_id'] == $orderItemData['physician_id']) {
            $selected = "selected";
        } else {
            $selected = "";
        }

        echo "<option value='".$row['physician_id']."' id='changePhysician".$row['physician_id']."' ".$selected." >".$row['physician_name']."</option>";
    } // /while 

?>

这是DB的截图： https://i.imgur.com/PYbUn1G.png

如何将数组转换为字符串？

0 个答案: