生成错误的输出无法获得正确的输出

Question

import re

NameAge =  '''
Janice is 22 and Theon is 33
Gabriel is 44 and Joey is 21
'''

names = re.findall (r'[A-Z][a-z]*', NameAge)
age = re.findall(r'\d{2}', NameAge)


ageDict = {}

x = 0

for eachname in names:

    ageDict[eachname] = age[0]
    x+=1

print(ageDict)

输出： {＆＃39; Gabriel＆＃39;：＆＃39; 22＆＃39;，＆＃39; Janice＆＃39;：＆＃39; 22＆＃39;，＆＃39; Joey＆＃39;：＆＃39; 22＆＃39;，＆＃39; Theon＆＃39;：＆＃39; 22＆＃39;}

Answer 1

你总是变老[0]。你应该把它改成年龄[x]

Answer 2

每当你获得第一个元素时。你必须去年龄[x]。

NameAge =  '''
Janice is 22 and Theon is 33
Gabriel is 44 and Joey is 21
'''
names = re.findall (r'[A-Z][a-z]*', NameAge)
age = re.findall(r'\d{2}', NameAge)
ageDict = {}
x = 0
for eachname in names:
   ageDict[eachname] = age[x]
   x+=1

print(ageDict)

输出：{'Gabriel'：'44'，'Janice'：'22'，'Joey'：'21'，'Theon'：'33'}