我想在许多模型中搜索多个字段。我不想使用其他应用程序,如'Haystack',只有纯Django。例如:
# models.py
class Person(models.Model):
first_name = models.CharField("First name", max_length=255)
last_name = models.CharField("Last name", max_length=255)
# other fields
class Restaurant(models.Model):
restaurant_name = models.CharField("Restaurant name", max_length=255)
# other fields
class Pizza(models.Model):
pizza_name = models.CharField("Pizza name", max_length=255)
# other fields
当我输入'Tonny'时,我应该得到:
Person
模特Restaurant
model pizza
模特的“Tonny's Special Pizza”。答案 0 :(得分:9)
一种解决方案是查询所有模型
# Look up Q objects for combining different fields in a single query
from django.db.models import Q
people = Person.objects.filter(Q(first_name__contains=query) | Q(last_name__contains=query)
restaurants = Restaurant.objects.filter(restaurant_name__contains=query)
pizzas = Pizza.objects.filter(pizza_name__contains=query)
然后结合结果,如果你想
from itertools import chain
results = chain(people, restaurants, pizzas)
好的,确定,这是一个更通用的解决方案。搜索所有型号的所有CharFields:
search_models = [] # Add your models here, in any way you find best.
search_results = []
for model in search_models:
fields = [x for x in model._meta.fields if isinstance(x, django.db.models.CharField)]
search_queries = [Q(**{x.name + "__contains" : search_query}) for x in fields]
q_object = Q()
for query in search_queries:
q_object = q_object | query
results = model.objects.filter(q_object)
search_results.append(results)
这将为您提供所有查询集的列表,然后您可以将其模制为您选择使用的格式。
要获取要填充search_models
的模型列表,您可以手动执行,或使用get_models
之类的内容。阅读文档以获取有关其工作原理的更多信息。