Question

这是一个简单地返回最小值及其在数组中出现的次数的程序。如果数组填充{13,28,5,11}，则返回min为5，计数为1.但是，当数组填充给定数字时，它返回计数为2，当它应为1时我该如何解决这个问题？三江源

public class Test4{
   public static void main(String[] args){
      int[] array = {4, 20, 30, 4, 25, 25, 6, 2, 29, 27, 1, 29, 11, 6, 10, 17, 8};
      findMin(array);
   }

   public static void findMin(int[] array) {
      if (array == null || array.length < 1)
         return;
      int count = 0;
      int min = array[0];

      for (int i = 1; i <= array.length - 1; i++) {

         if (min > array[i]) {
            min = array[i];  
            if(min == array[i]){

               count++;
            }
         }
      }
      System.out.println("The minimum is: " + min +"\n" + "The count is: " + count);
   }
}

Answer 1

您应该将计数初始化为1，并且每当更改当前最小值时重置为1：

  int count = 1; // initial count should be 1
  int min = array[0];

  for (int i = 1; i <= array.length - 1; i++) {
     if (min > array[i]) {
        // new minimum - reset count to 1
        min = array[i];
        count = 1;
     } else if (min == array[i]) {
         // same minimum - increment count
         count++;
     }
  }

计算int的出现次数

1 个答案: