无法在函数

时间:2017-10-17 00:46:08

标签: swift alamofire swxmlhash

我正在尝试从alamofire变量中更改全局变量,但我遇到了问题。这是我的代码:

var projects = [[String]]()
var xmlToParse = String()
var postTitle = String()
var postLink = String()

override func viewDidLoad() {
    super.viewDidLoad()

    httpRequest("https://www.hello.com/feed") { response in
        self.xmlToParse = response as String
        let xml = SWXMLHash.parse(self.xmlToParse)

        for elem in xml["rss"]["channel"]["item"].all {
            self.postTitle = elem["title"].element!.text
            self.postLink = elem["link"].element!.text                
            self.projects.append([self.postTitle, self.postLink])
        }
    }
    print(self.projects)
}

当我在这里打印self.projects时,我得到一个空数组,但是当我在httpRequest函数中打印它时,我得到了正确的数据。我没有在for循环中设置全局变量项目吗?我怎样才能获得该函数之外的值?我已经尝试过在SO上找到的所有内容但没有成功。非常感谢任何帮助。

更多信息,请参阅我的httpRequest函数:

func httpRequest(_ section: String, completion: @escaping (String) -> Void) {
    Alamofire.request(section, method: .get).responseString { response in
        completion(response.result.value!)
    }
}

1 个答案:

答案 0 :(得分:1)

假设xml [" rss"] [" channel"] [" item"]不是零...

override func viewDidLoad() {
    super.viewDidLoad()

    httpRequest("https://www.hello.com/feed") { response in
        self.xmlToParse = response as String
        let xml = SWXMLHash.parse(self.xmlToParse)

        for elem in xml["rss"]["channel"]["item"].all {
            self.postTitle = elem["title"].element!.text
            self.postLink = elem["link"].element!.text                
            self.projects.append([self.postTitle, self.postLink])
        }

        self.setup()
    }
}

func setup() {
    // Your logic here
}
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