Question

我正在使用mysql中的sql查询，例如我正在插入像键和值对

这样的记录

学生表

StdId StuName   phnNum 
1    John   87678

我正在student_metadata表中存储有关该学生的详细信息

S.NO FieldName   FieldValue     indexVal
1    college       St.Anns         1
2    Address      Arizona      1
3    IdNum         321             1

现在我想获取student_metadata

SELECT 
 student.stdId AS StdId
 fieldValue AS fieldValue
FROM 
Student 
 LEFT JOIN 
 Student_metadata ON Student.StdId = student_metadata.indexVal
Where 
 Student_metadata.fieldName IN ('College','IdNum')

我的问题是，如果我使用＆＃39; IN＆＃39;它给了我2行。如下所示

StudentId  fieldValue 
1       St.Anns
1           321

我想获取如下所示

StudentId  fieldValue IdNum
1       St.Anns    321

任何人都可以在此建议我

Answer 1

您可以使用条件聚合来进行透视：

select 
 s.stdid,
 max(case when m.fieldname = 'College' then fieldvalue end) as fieldvalue,
 max(case when m.fieldname = 'IdNum' then fieldvalue end) as idnum
from student s
left join student_metadata m on s.stdid = m.indexval
where m.fieldname in ('College','IdNum')
group by s.stdid

Answer 2

您可以使用数据透视表样式查询：

SELECT
    a.`StuName`,
    COALESCE(b.`FieldVal`) as `college`,
    COALESCE(c.`FieldVal`) as `IdNum`
FROM `Student` a
LEFT JOIN `student_metadata` b
ON b.`indexVal` = a.`StdId` AND b.`FieldName` = 'college'
LEFT JOIN `student_metadata` c
ON c.`indexVal` = a.`StdId` AND c.`FieldName` = 'IdNum'
WHERE a.`StdId` = 1
GROUP BY a.`StdId`

使用IN时如何只获取一条记录而不是获取2条记录

2 个答案: