Question

（标题有点奇怪，随意改变它，我不知道该放什么） HTML表将是MySQL表中最后5件事的历史记录，当第一行加载时，它存储在HTML表中第一行的变量中，然后加载/获取下一个MYSQL行，并且然后将HTML表中的第二行更改为MYSQL表的第二行。

示例：

for each row:
$username = row["username"]
$name = row["name"]

结果结果应该在HTML表格中：这些是使用上面的变量，根据MySQL表中的最后5个表，我需要它们是所有不同的数据

用户名一个Name1（MySQL第1行）两个Name2（MySQL第2行）三个Name3（MySQL第3行）四个Name4（MySQL第4行）

到目前为止

代码：

$stmt = $dbConnection->prepare("SELECT * FROM history ORDER BY id DESC LIMIT 5");
$stmt->execute();



foreach ($stmt as $row) {
    $username = $row['username'];
    $gamemode = $row['gamemode'];
    $winnings = $row['won'];
}

Answer 1

您可以使用PDOStatement::fetchAll方法执行此操作。我建议你避免从php构建HTML代码（如html表）。随意提问。

<?php
// Create a PDO instance as db connection to a MySQL db.
$dbConnection = new PDO(
        'mysql:host=localhost;port=3306;dbname=demo;charset=utf8'
        , 'user'
        , 'pass'
        , array(
    PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
    PDO::ATTR_EMULATE_PREPARES => FALSE,
    PDO::ATTR_PERSISTENT => TRUE
        )
);

$sql = 'SELECT * FROM history ORDER BY id DESC LIMIT 5';

$stmt = $dbConnection->prepare($sql);
$executed = $stmt->execute();

/*
 * Fetch the result set in form of an array.
 * It's used later to build the html table.
 * 
 *  Array
 *  (
 *      [0] => Array
 *          (
 *              [username] => one
 *              [name] => name1
 *          )
 *  
 *      [1] => Array
 *          (
 *              [username] => two
 *              [name] => name2
 *          )
 *  
 *      [2] => Array
 *          (
 *              [username] => three
 *              [name] => name3
 *          )
 *      ...
 *      [4] => Array
 *          (
 *              [username] => five
 *              [name] => name5
 *          )
 *  )
 */
$resultset = $stmt->fetchAll(PDO::FETCH_ASSOC);

// Just for testing. Delete this in the end.
echo '<pre>' . print_r($resultset, TRUE) . '</pre>';
?>

<!DOCTYPE html>
<html>
    <head>
        <meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1" />
        <meta name="viewport" content="width=device-width, initial-scale=1, user-scalable=yes" />
        <meta charset="UTF-8" />

        <title>Demo</title>
    </head>
    <body>

        <table>
            <tr>
                <td>Username</td>
                <td>Name</td>
            </tr>
            <?php
            // Loop through the resultset array and build each html row.
            foreach ($resultset as $row) {
                $username = $row['username'];
                $name = $row['name'];
                ?>
                <tr>
                    <td>
                        <?php echo $username; ?>
                    </td>
                    <td>
                        <?php echo $name; ?>
                    </td>
                </tr>
                <?php
            }
            ?>
        </table>
    </body>
</html>

Answer 2

为了保持代码尽可能接近，您可以使用数组来存储数据，如下所示：

$stmt = $dbConnection->prepare("SELECT * FROM history ORDER BY id DESC LIMIT 5");
$stmt->execute();

$usernames = array();
$gamemodes = array();
$winnings = array();

foreach ($stmt as $row) {
    $usernames[] = $row['username'];
    $gamemodes[] = $row['gamemode'];
    $winnings[] = $row['won'];
}

然后，您可以像这样访问它们：

echo $usernames[1]; // Second name

将3个变量用于大量数据

2 个答案: