我从IDLE运行但不在命令行运行Python脚本?

时间:2017-10-18 19:38:29

标签: python

我正在做一个学校项目,我们必须制作一个剧本。 基本上,每当我在IDLE中,我按F5运行脚本一切正常,但当我双击python文件本身并进入命令行时,我只能输入一个东西(R或L)和然后窗口关闭。为什么是这样 ?我认为分配的一个要求是它需要在命令行中执行,所以这就是我要问的原因。 这是我的剧本(它还没有完成)

import os
import csv
import sys


def main():
    menu()



def menu():
    print ("******MAIN MENU******")
    print()
    veryFirstChoice = input("Would you like to register an account, or log in? Type R to register and L to log in ").upper()
    if veryFirstChoice == "R":
        register()
    elif veryFirstChoice == "L":
        login()

def login():
    username = input("Please enter your username")
    password = input("Please enter your password")  
    for line in open("accountfile.txt","r").readlines():
        login_info = line.split()
        if username == login_info[0] and password == login_info[1]:
            print("Correct credentials!")
            return quiz()
    print("Incorrect credentials,please try again. ")
    return login()

def register():
    username = input("Please input the first 3 letters of your first name and your age ")
    password = input("Please input your desired password ")
    file = open("accountfile.txt","a")
    file.write(username)
    file.write(" ")
    file.write(password)
    file.write("\n")
    file.close()
    menu()

def quiz():
    choice1 = input ("""Would you like to take the Chemistry Quiz,or the Computer Science quiz ? Type in CH for Chemistry or CS for Computer Science """).upper()
    score = 0

    if choice1 == "CH":
        choice2 = input ("Would you like to do the easy, medium or hard questions ?").lower()
        if choice2 == "easy":
            load_profile = open("chemistryquiz.txt","r")
            lines = load_profile.read().splitlines()
            question1 = lines[4]
            question2 = lines[5]
            question3 = lines[6]
            question4 = lines[7]
            question5 = lines[8]
            print (question1)
            answer1 = input("Please enter your answer ").upper()
            if answer1 != "A":
                print ("You got the wrong answer, your score is", score)
            else:
                score1 = (score+1)
                print ("Your score is", score1)
            print (question2)
            answer2 = input("Please enter your answer ").upper()
            if answer2 != "A":
                score1 = score1
                print ("You got the wrong answer, your score is", score1)

            else:
                score2 = (score1+1)
                print ("Your score is", score2)
            print (question3)
            answer3 = input("Please enter your answer ").upper()
            score2 = score1
            if answer3 != "A":
                score3 = score2
                print ("You got the wrong answer, your score is", score3)
            else:
                score3 = (score2+1)
                print ("Your score is", score3)
            print (question4)
            answer4 = input("Please enter your answer ").upper()
            if answer4 != "A":
                score4 = score3
                print ("Wrong answer, your score is ", score4)
            else:
                score4 = (score3+1)
                print ("Your score is", score4)
            print (question5)
            answer5 = input("Please enter your answer ").upper()
            if answer5 != "A":
                score5 = score4
                print ("You got the wrong answer, your score is ", score5)
            else:
                score5 = (score4+1)
                print ("Well done, your score is ", score5)
        if choice2 == "medium":
            load_profile = open("chemistryquiz.txt","r")
            lines = load_profile.read().splitlines()
            question1 = lines[13]
            question2 = lines[14]
            print (question1)
            answer1 = input("Please enter answer ").upper()
            if answer1 != "A":
                score1 = score
                print ("Wrong answer ", score1)
            else:
                score1 = (score+1)
                print ("Noice, score is ", score1)

main()

2 个答案:

答案 0 :(得分:1)

我假设你在Windows上?

这是窗口控制台工作的方式;一旦其中运行的程序退出,它就会关闭。我猜你的程序以错误结束或者只是正常结束,在任何一种情况下,windows都会立即关闭控制台窗口(yay)。

避免这种情况的一种方法是在程序结束时添加input("press enter to exit.")。如果程序崩溃,这没有任何帮助,在这种情况下,Vinny上面的评论是要走的路:手动打开命令窗口,然后通过键入python然后通过路径来手动启动程序你的.py文件。如果您的程序出现错误,它将被打印出来,您将退回到cmd shell提示符。

答案 1 :(得分:0)

如果文件扩展名与python解释器关联,则可以通过双击运行它,问题是在脚本完成执行后立即关闭终端/ cmd窗口。要解决此问题,您有两个选择:

  1. input('Press enter to exit.')执行后,最后在脚本中添加一个阻止语句,例如main()。这样,在按下某个键后,脚本不会立即终止。

  2. 从脚本执行后将保留的终端/ cmd实例运行您的脚本