Question

我已在下面编写了一个正常运行的代码，我只想将我的菜单设置从程序中更改为外部。我被要求从程序外部的.txt文件中获取.txt文件中的sodaMachine内容，该程序将从.txt文件中获取并显示＆＃34;带上你的饮料（1。）＆＃34;。

我的问题是我要添加什么来获取一个准确接受int的程序，以及来自命令的.txt文件的字符串。所以，如果我输入＆＃34; 1。）＆＃34;该计划提取＆＃34;可口可乐＆＃34;及其价格（一个整数）＆＃34; 150＆＃34;。

  import java.lang.Math;
import java.util.Scanner;

public class CST1201 {

    private static Scanner input = new Scanner(System.in);

    public static void main(String[] args) {
        int coinTotal = 0;
        int coinTotal2 = 0; 
        int coinTotal3 = 0;
        int runAgain = 1;

        while(runAgain == 1)
            {
            while (coinTotal < 100){
                System.out.println("Please insert a coin ");
                coinTotal2 = input.nextInt();
                if (coinTotal2 != 25 && coinTotal2 != 5 && coinTotal2 != 10)
                {
                    coinTotal2 = 0;
                    while (coinTotal2 != 25 && coinTotal2 != 5 && coinTotal2 != 10)
                    {
                        System.out.println("Please insert a coin(5,10,25)");
                        coinTotal2 = input.nextInt();
                        if (coinTotal2 != 25 && coinTotal2 != 5 && coinTotal2 != 10)
                        {
                            coinTotal2 = 0;
                        }
                        else
                        {
                            coinTotal = coinTotal + coinTotal2;
                            coinTotal3 = coinTotal + coinTotal2;
                        }
                    }
                }
                else
                {
                    coinTotal = coinTotal + coinTotal2;
                }
                System.out.println("Total: " + coinTotal);
            }
            int choice = 0;
            System.out.println("What would you like? \n1.Coca-Cola \n2.Pepsi \n3.Orange Soda \n4.Grape Soda \n5.Mountain Dew \n6.Water");
            choice = input.nextInt();
            if (choice ==1) {
                System.out.println("Please take your Coca-Cola");
            } else {
                if(choice == 2) {
                    System.out.println("Please take your pepsi");
                } else {
                    if (choice == 3) {
                        System.out.println("Please take your Orange Soda");
                    } else {
                        if (choice == 4) {
                            System.out.println("Please take your Grape Soda");
                        } else {
                            if (choice == 5) {
                                System.out.println("Please take your Mountain Dew");
                            } else {
                                if (choice == 6) {
                                    System.out.println("Please take your water");
                                }
                               }
                              }
                             }
                            }
                           }
            int change;
            if (coinTotal > 100){
                change = coinTotal - 100;
                System.out.println("Please take your change: " + change);
            }
                System.out.println("Would you like to buy another drink?");
                runAgain = input.nextInt();
                if (runAgain == 1)
                {
                   coinTotal = 0;
                }
                else
                {
                    runAgain = 0;
                    System.out.println("Thank you");
                }

            }
    }
}

Answer 1

我假设你想从.txt文件中输入coinTotal，coinTotal2，coinTotal3，choice和runagain，并为给定的输入多次运行你的程序？

如果是这种情况，您可以将整个方法放入具有上述参数的函数中，并通过.txt输入文件循环提供参数。您可以使用文件和扫描程序从文件中读取内容，具体取决于文件在文件中的排列方式。

Scanner scan = new Scanner(new File("FileName")); // this gets you your file

您可以使用scan.next（）将文件元素作为1个字符串进行访问，然后将其解析为适当的需要，然后将其传递给您的函数。

希望有所帮助。

从.txt文件中读取，以便程序使用.txt文件中的变量和字符串进行更新

1 个答案: