Question

我有以下表格：用户

Schema::create('users', function (Blueprint $table) {
            $table->increments('id');
            $table->string('name');
            $table->string('username');
            $table->string('email')->unique();
            $table->string('password');
            $table->rememberToken();
            $table->timestamps();
            $table->integer('role_id')->unsigned();
            $table->foreign('role_id')->references('id')->on('roles');

领域

Schema::create('areas', function (Blueprint $table) {
            $table->increments('id');
            $table->string('name');
            $table->integer('location_id')->unsigned();
            $table->foreign('location_id')->references('id')->on('locations')->onDelete('cascade');
            $table->timestamps();

area_user

Schema::create('area_user', function (Blueprint $table) {
            $table->increments('id');
            $table->integer('user_id')->unsigned();
            $table->foreign('user_id')->references('id')->on('users');
            $table->integer('area_id')->unsigned();
            $table->foreign('area_id')->references('id')->on('areas');
        });

建筑物

Schema::create('buildings', function (Blueprint $table) {
            $table->increments('id');
            $table->string('name');
            $table->string('symbol')->nullable();
            $table->integer('area_id')->unsigned();
            $table->foreign('area_id')->references('id')->on('areas')->onDelete('cascade');
            $table->integer('building_type')->unsigned();
            $table->foreign('building_type')->references('id')->on('building_types');
            $table->timestamps();
        });

用户模型：

public function areas()
    {
        return $this->belongsToMany('App\Area');
    }

区域模型：

public function users(){
        return $this->belongsToMany('App\User');
    }

建筑模型：

public function area(){
       return $this->belongsTo('App\Area','area_id');
    }

如何在用户模型中编写一个查询，返回通过其指定区域（area_user表）分配给用户的所有建筑物我尝试了这个，但它返回了一个错误

Building::whereHas('area', function ($q) {
            $q->whereHas('users', function ($q) {
                $q->where('id', auth()->id());
            });
        })->get();

错误：

SQLSTATE[23000]: Integrity constraint violation: 1052 Column 'id' in where clause is ambiguous (SQL: select * from `buildings` where exists (select * from `areas` where `buildings`.`area_id` = `areas`.`id` and exists (select * from `users` inner join `area_user` on `users`.`id` = `area_user`.`user_id` where `areas`.`id` = `area_user`.`area_id` and `id` = 11))) (View: C:\xampp\htdocs\hse\resources\views\observations\form_observation.blade.php) (View: C:\xampp\htdocs\hse\resources\views\observations\form_observation.blade.php)

Answer 1

您可以通过在where子句中指定表来解决歧义：

更改

$q->where('id', auth()->id());

要

$q->where('users.id', auth()->id());

使用whereHas eloquent relationship query

1 个答案: