Question

我有下一个结构的数组：

$collection = array (
    array('category' => 'buildings',
          'id' => 9),
    array('category' => 'buildings',
          'id' => 8),
    array('category' => 'trees',
          'id' => 11),
    array('category' => 'trees',
          'id' => 12),
    array('category' => 'trees',
          'id' => 11),
)

我需要创建下一个集合：

array ('buildings' => array (9, 8),
       'trees' => array (10, 12, 11),
)

所以我用它来foreach（）和array_push（）。首先，如果新集合不是当前类别。如果没有，我设置空数组，将id推送到它。但是如果类别存在于新集合中，我将id值推送到数组ans添加到集合中。所以我的代码是：

function getCategoriesAndTypes($collection)
{
    $categoriesAndTypes = [];
    $typesCollection = [];
    foreach ($collection as $object) {
    $category = $object['category'];

    if (! array_key_exists($category, $categoriesAndTypes)) {
        $typesCollection = [];
        array_push($typesCollection, $object['type']);
        $categoriesAndTypes[$category] = $typesCollection;
    } else {
        array_push($typesCollection, $object['type']);
        $categoriesAndTypes[$category] = $typesCollection;
    }

}

return $categoriesAndTypes;
}

但我认为存在更多漂亮的解决方案！你能帮我重构我的代码吗？谢谢！

Answer 1

我已将我的代码重构为下一个版本：

function getCategoriesAndTypesFromLibraryFolder($collection)
{
    $categoriesAndTypes = [];
    $typesCollection = [];

    foreach ($collection as $object) {
        if (! array_key_exists($object['category'], $categoriesAndTypes)) {
            $typesCollection = [];
        }

        array_push($typesCollection, $object['type']);
        $categoriesAndTypes[$object['category']] = $typesCollection;
    }

    return $categoriesAndTypes;
}

你有没有想过让它变得更好？

Answer 2

以下方法就足够了：

function getCategoriesAndTypesFromLibraryFolder($collection)
{
    $categoriesAndTypes = [];

    foreach ($collection as $item) {
        $categoriesAndTypes[$item['category']][] = $item['id'];
    }

    return $categoriesAndTypes;
}

结果是：

array ( 'buildings' => array ( 0 => 9, 1 => 8, ), 
        'trees' => array ( 0 => 11, 1 => 12, 2 => 11, ), )

基于另一个数组创建新数组

2 个答案: