SQL将具有相同ID的行合并为一个

Question

目前我有以下表格：

ID                                      Date        Number
-------------------------------------------------------
F78D56A2-5BF1-4172-90BA-23CAF6A05A10    NULL        NULL
F78D56A2-5BF1-4172-90BA-23CAF6A05A10    NULL        NULL
F78D56A2-5BF1-4172-90BA-23CAF6A05A10    NULL        001234
F78D56A2-5BF1-4172-90BA-23CAF6A05A10    2018-11-30  NULL

请求的输出是：

ID                                      Date        Number
-------------------------------------------------------
F78D56A2-5BF1-4172-90BA-23CAF6A05A10    2018-11-30  001234

当然你不能使用group by，因为这需要更多的论据。我怎么能这样做？

Answer 1

您可以尝试加入以避免GROUP BY

SELECT T1.Id, MAX(T1.Date) AS Date, MAX(T1.Number) As Number
FROM YourTableName AS T1
JOIN YourTableName AS T2 ON T1.column_name = T2.column_name;