Ruby数组的数组为哈希数组

Question

我有一个数组数组：

data = [
 ["Smith", "Bob", "Male"], 
 ["Jim", "Tim", "Male"],   
 ["Welch", "Anne", "Female"]
]

我如何将其转换为：

data = [
 {:first_name => "Smith", :last_name => "Bob", :gender => "Male"},  
 {:first_name => "Jim", :last_name => "Tim", :gender => "Male"}, 
 {:first_name => "Welch", :last_name => "Anne", :gender => "Female"}
]

Answer 1

您可以这样做：

fields = [:first_name, :last_name, :gender]
data.map {|row| fields.zip(row).to_h }

#=> [{:first_name=>"Smith", :last_name=>"Bob", :gender=>"Male"}, {:first_name=>"Jim", :last_name=>"Tim", :gender=>"Male"}, {:first_name=>"Welch", :last_name=>"Anne", :gender=>"Female"}] 

请注意，只有元素与字段的顺序相同时才会有效。

Answer 2

您也可以使用Struct：

presenter = Struct.new(:first_name, :last_name, :gender)
data.map { |e| presenter.new(*e).to_h }
#=> [{:first_name=>"Smith", :last_name=>"Bob", :gender=>"Male"}, 
#    {:first_name=>"Jim", :last_name=>"Tim", :gender=>"Male"}, 
#    {:first_name=>"Welch", :last_name=>"Anne", :gender=>"Female"}]

Answer 3

fields = [:first_name, :last_name, :gender]
data.map{|d| Hash[fields.zip(d)]}