Question

<!DOCTYPE html>
<html>
    <head>
        <title>Data</title>
    </head>

    <body>
        /* POST it here  */
        <form  action="this.php" method="post">
            <input type='text' name='SpouseName' required/>
            <input type='text' name='SpouseAge' /> 
            <input type="submit" name="submit" value="SUBMIT"/>
        </form>
    </body>
</html>

/* Here is the PHP CODE */
<?php   
include 'dbh2.php'; 
$SpouseName = $_POST['SpouseName']; 
$SpouseAge = $_POST['SpouseAge'];  
$sql = "INSERT INTO test (SpouseName, SpouseAge) VALUES ('$SpouseName', '$SpouseAge')";    
$result = $conn->query($sql);   
?>

我想忽略像spouseage这样的空输入怎么做？

Answer 1

您可以检查是否已使用 isset() 设置了值，并使用 !empty() 检查它们是否为空：

$_POST

虽然请注意，在分配变量之前，最好检查if (isset($_POST['SpouseName']) && !empty($_POST['SpouseName'])) { $SpouseName = $_POST['SpouseName'] } if (isset($_POST['SpouseAge']) && !empty($_POST['SpouseAge'])) { $SpouseAge = $_POST['SpouseAge']; } if ($SpouseName && $SposeAge) { $sql = "INSERT INTO test (SpouseName,SpouseAge) VALUES ('$SpouseName','$SpouseAge')"; } else { echo "The values weren't set or were empty!"; }值是否已设置且不为空：

public void drawPolygons(int numberOfPolygons){
    for(int i=0; i<numberOfPolygons; i++){
        drawPolygon(numberOfSides, lengthOfSide, penColor);
    }
}

希望这会有所帮助：）

Answer 2

我将查询分为两部分。现在，您可以对每个单独的输入进行表单验证并测试数据。我还为提交设置了isset，以检查是否已被点击。然后我们测试它是否为空，如果不插入，我们为每个都做。

if(isset($_POST['submit'])){
$SpouseName = $_POST['SpouseName'];
$SpouseAge = $_POST['SpouseAge'];
if(!$SpouseName==''){$sql = "INSERT INTO test (SpouseName) VALUES ('$SpouseName')";}
if(!$SpouseAge ==''){$sqlb = "INSERT INTO test (SpouseAge) VALUES ('$SpouseAge')";
} 
}

保存到数据库时如何忽略空输入

2 个答案: