Question

我正在用Python编写一个简单的程序。但我无法理解为什么它不存储Hcount，Scount和Fcount的值。此外，它没有正确显示税。任何帮助将不胜感激

while True:

print("MacDoogle's:")
print("1. Hamburger = $1.50")
print("2. Soda      = $1.15")
print("3. Fries     = $1.25")
print("4. Complete Order")


choice = int(input('Make a selection: '))
while choice < 1 or choice > 4:
    choice = int(input('Enter a valid selection: '))

Hcount =0
Scount =0
Fcount =0 

if choice > 0 and choice <4:

    if choice == 1:
        amount1=int(input("Enter number of Hamburgers: "))
        Hcount += amount1

    elif choice == 2:
        amount2=int(input("Enter number of Sodas: "))
        Scount += amount2

    elif choice == 3:
        amount3=int(input("Enter number of Fries: "))
        Fcount += amount3

if choice == 4:
    sub=int((Hcount * 1.50) + (Scount * 1.15) + (Fcount * 1.25))
    tax=int(sub * 0.09)
    total=int(sub + tax)
    print('Number of Hamburgers:', format(Hcount, '3.0f'))
    print('Number of Sodas:', format(Scount, '3.0f'))
    print('Number of Fries:', format(Fcount, '3.0f'))
    print('Subtotal:', format(sub, '3.2f'))
    print('Tax:', format(tax, '3.2f'))
    print('Total:', format(total, '3.2f'))
    break

Answer 1

这不是https://codereview.stackexchange.com/但是我有点无聊并想帮助你

正确缩进代码 - 每if，elif或while语句后应有4个缩进空格
将您的计数器变量移到while循环
将变量更改为小写名称，而不是将第一个字母大写
if choice > 0 and choice < 4可以重写为0 < choice < 4
您的if choice > 0 and choice < 4是多余的。您可以删除此
你的内部while循环是多余的 - 你根本不需要这个
您可以在if语句中重复使用相同的变量名称，无需创建amount0，amount1和amount2
在计算小计和税额时，您不应该将值转换为int() - 这会从您的数字中删除小数位，从而导致您的税收从未计算过。

格式化字符串时，如果要将其格式化为2位小数，可以使用'Subtotal: {:0.2f}'.format(sub)

hcount = 0
scount = 0
fcount = 0

while True:
    print("MacDoogle's:")
    print("1. Hamburger = $1.50")
    print("2. Soda      = $1.15")
    print("3. Fries     = $1.25")
    print("4. Complete Order")

    choice = int(input('Make a selection: '))

    if choice == 1:
        amount = int(input("Enter number of Hamburgers: "))
        hcount += amount
    elif choice == 2:
        amount = int(input("Enter number of Sodas: "))
        scount += amount
    elif choice == 3:
        amount = int(input("Enter number of Fries: "))
        fcount += amount
    elif choice == 4:
        sub = (hcount * 1.50) + (scount * 1.15) + (fcount * 1.25)
        tax = sub * 0.09
        total = sub + tax

        print('Number of Hamburgers: {0}'.format(hcount))
        print('Number of Sodas: {0}'.format(scount))
        print('Number of Fries: {0}'.format(fcount))
        print('Subtotal: {:0.2f}'.format(sub))
        print('Tax: {:0.2f}'.format(tax))
        print('Total: {:0.2f}'.format(total))
        break

Answer 2

这是因为每次循环迭代时，Hcount，Scount，Fcount都被赋值为0。将Hcount =0 Scount =0 Fcount =0放在while循环前面，它应该可以解决您的问题

Answer 3

这个强制转换为int会丢弃小数点右边的内容。考虑将所有内容存储在美分中，然后乘以100

    sub_in_cents = (hcount * 150) + (scount * 115) + (fcount * 125)
    tax_in_cents = int(sub * 0.09)
    total_in_cents = sub_in_cents + tax_in_cents
    total_in_dollars = total_in_cents*1./100

Python 3.5快餐计算器

3 个答案: