Question

我试图弄清楚为什么这个简单的代码会产生语法错误。有什么建议吗？

./g.sh: line 4: syntax error in conditional expression: unexpected token `;'
./g.sh: line 4: syntax error near `;'
./g.sh: line 4: `    if [[ "$y" == "rsa" ]]; then'

以下是代码：

for x in *; do
  for y in rsa ed25519; do
    yb=''
    if [[ "$y" == "rsa" ]]; then
      yb=' -b 4096'
    fi
    echo "x: ${x} y: ${y} yb: ${yb}"
  done
done

这只是用于为许多机器自动生成rsa / ed25519密钥的测试代码。

一些额外的信息：

Ubuntu Server 17.10
GNU bash 4.4.12

Answer 1

nano 2.sh

for x in *; do
 for y in rsa ed25519; do
 yb=''
  if [[ "$y" == "rsa" ]]; then
   yb=' -b 4096'
  fi
 echo "x: ${x} y: ${y} yb: ${yb}"
 done
done}

chmod + x 2.sh

/2.sh

x: 1.sh y: rsa yb:  -b 4096
x: 1.sh y: ed25519 yb: 
x: 2.sh y: rsa yb:  -b 4096
x: 2.sh y: ed25519 yb: 
x: abc.txt y: rsa yb:  -b 4096
x: abc.txt y: ed25519 yb: 
x: dene.csv y: rsa yb:  -b 4096
x: dene.csv y: ed25519 yb: 
x: deneme y: rsa yb:  -b 4096
x: deneme y: ed25519 yb: 
x: dene.sh y: rsa yb:  -b 4096
x: dene.sh y: ed25519 yb: 
x: dene.txt y: rsa yb:  -b 4096
x: dene.txt y: ed25519 yb: 
x: Desktop y: rsa yb:  -b 4096
x: Desktop y: ed25519 yb: 
x: Downloads y: rsa yb:  -b 4096
x: Downloads y: ed25519 yb:

GNU bash，版本4.4.12

Parrot 4.11.6-1parrot6 enter code here

如果条件，则Bash语法错误

1 个答案: