在没有固定角度的图像上绘制旋转的边界框

Question

我是编程和opencv的新手，我尝试使用颜色分割检测硬盘。到目前为止，我的代码加载图像，创建3个不同颜色的蒙版，并在非零点周围绘制一个直立的边界框：

int main( int argc, char** argv )
{

//Load the image
Mat img = imread(argv[1], 1);
if (img.empty()){
cout << "No image found..." << endl;
return -1;
}

//Extracting colors - BGR
Mat silver, white, black;

//Silver
inRange(img, Scalar(180, 180, 180), Scalar(200, 200, 200), silver);

//White
inRange(img, Scalar(240, 240, 240), Scalar(255, 255, 255), white);

//Black
inRange(img, Scalar(0, 0, 0), Scalar(30, 30, 30), black);

// logical OR mask
Mat1b mask = silver | white | black;

// Find non zero pixels
vector<Point> pts;

findNonZero(mask, pts);

cout << "Non-Zero Locations = " << pts << endl << endl; // get non zero coordinates

// Compute bounding box

Rect box = boundingRect(pts);

// Show bounding box
rectangle(img, box, Scalar(0, 0, 255), 3);
namedWindow("box", CV_WINDOW_NORMAL);
imshow("box", img); 
imshow("mask", mask);

waitKey(0);
destroyAllWindows;

return 0;}

现在我想绘制最小的边界框，所以我尝试使用

cv::RotatedRect box2 = cv::minAreaRect(pts);

代替。但是，当我尝试通过替换

来实现可视化时，它不会编译

Rect box = boundingRect(pts); 

与

RotatedRect box2 = minAreaRect(pts);

错误输出：

error: no matching function for call to ‘rectangle(cv::Mat&, cv::RotatedRect&, cv::Scalar, int)’
 rectangle(img, box2, Scalar(0, 0, 255), 3);

Answer 1

根据cv::Rectangle Opencv Docs，该函数只有两个变体：

void rectangle(Mat& img, Point pt1, Point pt2, const Scalar& color, int thickness=1, int lineType=8, int shift=0)

void rectangle(Mat& img, Rect rec, const Scalar& color, int thickness=1, int lineType=8, int shift=0 )

很明显它只接受cv::Rect或cv::Point。因此，没有规定直接输入cv::RotatedRect，因此您会收到上述错误。

要解决此问题，您可以使用以下内容提取cv::RotatedRect的4个点

cv::Point2f points[4];
rotatedRect.points(points);

然后使用cv::line()成对绘制边缘：

cv::RotatedRect rotatedRect = cv::RotatedRect(cv::Point(70, 70), cv::Size(90, 90), 30);

cv::Mat canvas = cv::Mat(200, 200, CV_8UC3, cv::Scalar(255, 255, 255));

cv::Point2f points[4];
rotatedRect.points(points);

cv::line(canvas, points[0], points[1], cv::Scalar(0, 255, 0), 3);
cv::line(canvas, points[1], points[2], cv::Scalar(0, 255, 0), 3);
cv::line(canvas, points[2], points[3], cv::Scalar(0, 255, 0), 3);
cv::line(canvas, points[3], points[0], cv::Scalar(0, 255, 0), 3);