Question

我试图使用php获取文本xpath / html但是没有成功任何想法。

实施例： https://safeweb.norton.com/report/show?url=google.com

我的xpath（这是正确的我已经仔细检查） //*[@id="bodyContent"]/div/div/div[3]/div[1]/div[1]/div[2]/div[1]/div/b

我希望使用php

在<div> result </div>显示结果

以下是我的代码：

<?php
public function getNortonSafe($domain)
{
  try
  {
    $callback_url = "https://safeweb.norton.com/report/show?url=google.com"; //. $domain;

    $curl_response = $this->curl->get($callback_url);

    if ($curl_response->headers['Status-Code'] == "200") {

      libxml_use_internal_errors(TRUE);
      $this->dom_doc->loadHTML($curl_response);
      libxml_use_internal_errors(FALSE);

      $xpath = new DOMXPath($this->dom_doc);
      $tmp = $xpath->query('//*[@id="bodyContent"]/div/div/div[3]/div[1]/div[1]/div[2]/div[1]/div/b')->item(0)->textContent);

      $tmp = explode(' ', trim($tmp));
      $norton_site_test = str_replace(",", "", $tmp[0]);

    } else {
      $norton_site_test = "0";
    }

    $response = array(
      'status' => 'success',
      'data' => array(
        'norton_site_test' => filter_var($norton_site_test, FILTER_SANITIZE_STRING)
      )
    );

  }
  catch (Exception $e)
  {
    $response = array(
      'status' => 'error',
      'msg' => $e->getMessage()
    );
  }
  return $response;
}
?>

HTML

<body>
<p id="norton_site_test">  result-text-here </p>
</body>

Answer 1

执行$xpath->query('some xpath here')->text(0)行时会发生错误：Fatal error: Call to undefined method DOMNodeList::text()。请检查您的PHP error reporting设置。

DOMXPath::query方法返回仅DOMNodeList方法的item对象（请参阅DOMNodeList）。你需要打电话：

$xpath->query('some xpath here')->item(0)->textContent

从接收到的DOMNodeList对象中获取第一个节点的文本内容。

Answer 2

关于此代码的更新，感谢@camelsWrite - 它现在正在工作！使用这个干净的代码并进行测试：

    

    public function getNortonSafe($domain)
    {
        try
        {
            $callback_url = "https://safeweb.norton.com/report/show?url= . $domain; //e.g $url: "https://safeweb.norton.com/report/show?url=google.com

            $curl_response = $this->curl->get($callback_url);

            if ($curl_response->headers['Status-Code'] == "200") {

                libxml_use_internal_errors(TRUE);
                $this->dom_doc->loadHTML($curl_response);
                libxml_use_internal_errors(FALSE);

                $xpath = new DOMXPath($this->dom_doc);
                $tmp = $xpath->query('//*[@id="bodyContent"]/div/div/div[3]/div[1]/div[1]/div[2]/div[1]/div/b')->item(0)->textContent);

                $tmp = explode(' ', trim($tmp));
                $norton_site_test = str_replace(",", "", $tmp[0]);

            } else {
                $norton_site_test = "0";
            }

            $response = array(
                'status' => 'success',
                'data' => array(
                    'norton_site_test' => filter_var($norton_site_test)
                )
            );

        }
        catch (Exception $e)
        {
            $response = array(
                'status' => 'error',
                'msg' => $e->getMessage()
            );
        }
        return $response;
    } ?>

如何使用php从xpath获取结果？

2 个答案: