Question

start = [0,0,0,0,0,0,0,0,0]
def print_board(turn, board):
    print(turn + " turn" + "\n   {}{}{}\n   {}{}{}\n   {}{}{}".format(board))
current_turn = "your"
print_board(current_turn, start)

以上内容给出了

Traceback (most recent call last):
  File "so.py", line 5, in <module>
    print_board(current_turn, start)
  File "so.py", line 3, in print_board
    print(turn + " turn" + "\n   {}{}{}\n   {}{}{}\n   {}{}{}".format(x for x in board))
IndexError: tuple index out of range

我的元组或列表中有9个值，9个大括号。正确？

Answer 1

format方法需要单个参数而不是单个列表。但您可以通过更改：

轻松修复它

"...".format(board)

为：

"...".format(*board)

星号*将使列表元素作为单独的参数传递。

Answer 2

print的值列表中只有一个项目 - 列表。你需要拆分各个整数。

def print_board(turn, board):
    print(turn + " turn" + "\n   {}{}{}\n   {}{}{}\n   {}{}{}".format(
        board[0], board[1], board[2],
        board[3], board[4], board[5],
        board[6], board[7], board[8]
    ))

Answer 3

我不认为'格式'与列表一样。我相信你需要这样的东西。

x=[1,2]
print('one + {} = {}'.format(x[0],x[1]))

元组索引超出范围python

3 个答案: