Question

我有一个数据框如下，

                     SP        IS
group2      
Control             669303.62   0.00
Test - NonRedeemers 1888366.53  -1219062.91
Test - Redeemers    709095.22   -39791.60

我需要计算差异变化的百分比，我想要使用的公式是(df['IS']/df.loc['Control'].iat[0])*100

我应用它但我需要绝对值的百分比。非常感谢任何帮助

Answer 1

似乎你需要：

a = ((df['IS']/df.loc['Control'].iat[0])*100).abs()
print (a)
group2
Control                  0.000000
Test - NonRedeemers    182.138998
Test - Redeemers         5.945224
Name: IS, dtype: float64

a = df['IS'].div(df.loc['Control'].iat[0]).mul(100).abs()
print (a)
group2
Control                  0.000000
Test - NonRedeemers    182.138998
Test - Redeemers         5.945224
Name: IS, dtype: float64

数据集上差异变化的百分比

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