Question

我正在使用xcode 9 beta 5.我试图解析网址。虽然基于url维护会话代码会给出语法错误。

 static func fetchFeatureApp(){
        let urlString="http://ebmacs.net/ubereats/Api/all_product?id=1"
        URLSession.shared.dataTask(with: NSURLRequest(url: urlString)) { (data, responce, error) in
            if error!=nil
            {
                print(error)
                return

            }
        }.resume()
    }

image description here

URLSession.shared.dataTask(with: NSURLRequest(url: urlString)) { (data, responce, error) in

这行代码给出了错误

无法转换类型＆＃39;字符串＆＃39;的值预期参数类型＆＃39; URL＆＃39; 如何纠正这个

如何删除此错误？我访问了这个link

Answer 1

URLRequest需要URL而不是String，这是错误消息所指出的内容。

let urlString = "http://ebmacs.net/ubereats/Api/all_product?id=1"
let url = URL(string: urlString)!
URLSession.shared.dataTask(with: URLRequest(url: url)) { (data, responce, error) in ...

您访问过的链接会从字符串中清楚地创建URL。

但实际上，您不需要URLRequest来获取简单的GET请求，只需通过URL

let url = URL(string: "http://ebmacs.net/ubereats/Api/all_product?id=1")!
URLSession.shared.dataTask(with: url) { (data, responce, error) in ...

Answer 2

嗨，这是我最喜欢的urlsession下载代码，

var request = URLRequest(url: URL(string: "Your URL String")!)

request.httpMethod = "POST"
let session = URLSession.shared
session.dataTask(with: request) {data, response, error in
     let parsedData = try JSONSerialization.jsonObject(with: data!) //if you want to convert to Json  
 }.resume()

使用session从url获取Json

2 个答案: