Question

我的网址有查询字符串，如下所示：

?v=11&icid=someid&near=far
OR
?icid=some&v=11&near=far
OR
?icid=some&near=far&v=11
OR
?v=11
OR
There may be more but "v" exists

在htaccess中，我该怎么办呢？

如果存在密钥“v” 和价值不是[1-11] 重定向到我的网站

到目前为止，我有以下内容：

示例网址：http://www.mysite.com/2010/01/17/breaking-news/？（上述QS之一）

RewriteCond％{QUERY_STRING} v
RewriteCond％{QUERY_STRING} v =（[^ 1-11] +）
RewriteRule（[1000-9999] +）/（[^ /] +）/（[^ /] +）/（[^ /] +）/？（[0-99] +）？$ http：//％ {HTTP_HOST} /？ [R，L]

非常感谢任何帮助。

谢谢，
大号

Answer 1

RewriteCond %{QUERY_STRING} v=([^&]+)
RewriteCond %1 !^(?:\d|11)$
RewiteRule ... stuff

Answer 2

这是我的尝试：

#grab the v parameter, allowing it to appear anywhere within the query string,
#without matching part of another parameter name such as "gov"
RewriteCond %{QUERY_STRING} (?:^|&)v=([^&]*)(?:$|&)

#check if it's NOT set to a digit between 1-11
RewriteCond %1 !^(?:[1-9]|1[01]?)$

#Begin matching anywhere within the requested URL, since there's no leading caret.
#If this should match the beginning, and not somewhere within the middle,
#then add a leading caret.
#The logic is as follows:
#Check if we have a number between 1000 and 9999 followed by a slash;
#then three slash delimited chunks with slashes in between;
#then an optional chunk which, if matched, must begin with a slash, then 
#a number between 0 and 99 (including a leading zero);
#followed by an optional tailing slash;
#followed by the end of the string.
RewriteRule ([1-9]\d{3})/([^/]+)/([^/]+)/([^/]+)(?:/(\d\d?))?/?$ http://%{HTTP_HOST}/? [R,L]

#more rules can go here if we didn't redirect

检查查询字符串中是否存在密钥 - htaccess

2 个答案: