如何从一个函数调用变量，以便您可以使用另一个函数？

Question

在下面，我有一个代码怪物。

def battle(oppatk, oppdef, opphealth, oppeva, oppspe, oppname):
    var1 = 0
    while True:
        if var1 > 0:
            if speed > oppspe:
                playerattack(oppdef, playerattack(oppdef, opphealth, oppeva, oppname), oppeva, oppname)
                opponentattack(oppatk, opponentattack(oppatk, health, defense, oppname, evasion), defense, oppname, evasion)
            elif oppspe > speed:
                opponentattack(oppatk, opponentattack(oppatk, health, defense, oppname, evasion), defense, oppname, evasion)
                playerattack(oppdef, playerattack(oppdef, opphealth, oppeva, oppname), oppeva, oppname)
            else:
                aaa = random(0, 1)
                if aaa == 0:
                    opponentattack(oppatk, opponentattack(oppatk, health, defense, oppname, evasion), defense, oppname, evasion)
                    playerattack(oppdef, playerattack(oppdef, opphealth, oppeva, oppname), oppeva, oppname)
                else:
                    playerattack(oppdef, playerattack(oppdef, opphealth, oppeva, oppname), oppeva, oppname)
                    opponentattack(oppatk, opponentattack(oppatk, health, defense, oppname, evasion), defense, oppname, evasion)

基本上发生的事情是它经历了游戏片和对手攻击功能，取决于哪个更快，玩家或对手。但是，当我调用其返回值的其中一个函数在下次运行时使用时，它会改为执行某种子级代码而不会对程序产生实际影响。您如何编写代码来避免这种情况？