获取所有未关注用户的用户2

Question

示例：我想让所有不关注id 2用户的用户

表追随者

   id     |   user_id   |  follower_id

    1            2             7
    2            2             8

表用户

id  |  username  | e-mail  | group

Answer 1

我不是mysql专家，但我相信伪sql会是：

select users.* from users where users.id is in (select distinct follower_id from followers where followers.user_id != 2)

！= 表示不同。

Answer 2

试一试：

Select users.* 
from users 
where users.id not in (
    select followers.follower_id 
    from followers 
    where followers.user_id = "2"
)