如何在Fileuploader中传递url作为参数?

时间:2017-11-12 07:28:02

标签: javascript angularjs file-upload

我有多个后端api用于上传照片,我想通过参数传递网址。

插件的链接:github

var uploader = $scope.uploader = new FileUploader({

      url: PASS_FILE_NAME, // here i want to pass apis through paramters

      queueLimit: 1,

      removeAfterUpload: true,
  });

  // FILTERS

  uploader.filters.push({

      name: 'imageFilter',

      fn: function(item /*{File|FileLikeObject}*/, options) {

          var type = '|' + item.type.slice(item.type.lastIndexOf('/') + 1) + '|';

      return '|jpg|png|jpeg|bmp|gif|'.indexOf(type) !== -1;

      }

  });

0 个答案:

没有答案
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