对于循环不在终点处停止

时间:2017-11-12 16:02:47

标签: r for-loop

我有一些R代码尝试在方阵A上完成LU分解。但是当我尝试运行代码时,我得到一个错误说;

Error in U[j, i] : subscript out of bounds

似乎变量j的for循环没有停止,起初我认为这是因为i变量循环到nrow(A) - 1,然后在结束循环之前加1,类似于C但是,我打印出i,j和k变量,似乎j变量没有停止。任何想法都是为什么?

LUD <- function(A) {

    if (!is.matrix(A)) {
        warning("argument is not a matrix: returning NA")
        return(NA)
    }
    L <- matrix(nrow = nrow(A), ncol = ncol(A))
    P <- matrix(nrow = nrow(A), ncol = ncol(A))
    for (i in 1:nrow(A)) {
        for (j in 1:nrow(A)) {
            if (i == j) {
                L[i, j] = 1
                P[i, j] = 1
            } else {
                L[i, j] = 0
                P[i, j] = 0
            }
        }
    }
    U = A

    for (i in 1:(nrow(A) - 1)) {

        max = which(U == max(U[i:nrow(A), i]), arr.ind = TRUE)
        k[i] = max[, 1]  ##finding position of largest element 

        temp = U
        U[i, ] = temp[k[i], ]  ## pivoting rows in U
        U[k[i], ] = temp[i, ]

        temp = L
        L[i, ] = temp[k[i], ]  ## pivoting rows in L
        L[k[i], ] = temp[i, ]

        temp = P
        P[i, ] = temp[k[i], ]  ##pivoting rows in P
        P[k[i], ] = temp[i, ]
        print(i)
        for (j in i + 1:nrow(A)) {
            print(j + 10)
            L[j, i] = U[j, i]/U[i, i]

            for (k in i:nrow(A)) 
            {
                U[j, k] = U[j, k] - L[j, i] * U[i, k]
                print(k + 100)
            }
        }
    }
}

编辑:这是我的矩阵:

A<-matrix(1:16,nrow=4,ncol=4)

1 个答案:

答案 0 :(得分:2)

我的猜测是你需要查看循环的序列。尝试 改变第二个循环     for(j in i + 1:nrow(A)) 至     for(j in (i + 1):nrow(A))

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