Mysql Group_Concat函数

时间:2011-01-18 15:03:12

标签: mysql group-concat

不了解如何使用GROUP_CONCAT函数,因为我的查询似乎重复了我实际上并不想要的值。

我有三张桌子:

------------------
Content
------------------
cid | title
2334 | Lorem Ipsum

------------------
Organizers
------------------
cid | name | sort
2334 | John Doe | 0

------------------
Participants
------------------
cid | name | sort
2334 | Jane Doe | 0
2334 | Bob Hope | 1
2334 | Bart Simpson | 2

我正在尝试编写一个将产生的查询:

cid | title | organizers | participants
2334 | Lorem Ipsum | John Doe | Jane Doe, Bob Hope, Bart Simpson

所以,我正在尝试使用GROUP_CONCAT。但是,值正在重复,所以我不确定如何输出我正在寻找的结果?

SELECT GROUP_CONCAT(co.name) as organizers, 
GROUP_CONCAT(cp.name) FROM content n 
LEFT JOIN organizers co ON n.cid = co.cid 
LEFT JOIN participants cp ON n.cid = cp.cid 
WHERE n.cid = 2334

以上产量:

cid | title | organizers | participants
2334 | Lorem Ipsum | John Doe, John Doe, John Doe | Jane Doe, Bob Hope, Bart Simpson

2 个答案:

答案 0 :(得分:2)

select group_concat(distinct co.name)

详细信息:http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html#function_group-concat

<强>语法

GROUP_CONCAT([DISTINCT] expr [,expr ...]
[ORDER BY {unsigned_integer | col_name | expr}
[ASC | DESC] [,col_name ...]]
[SEPARATOR str_val])

答案 1 :(得分:1)

SELECT n.cid, n.Title,
  GROUP_CONCAT(DISTINCT co.name ORDER BY co.sort) as organizers, 
  GROUP_CONCAT(cp.name ORDER BY cp.sort) 
FROM Content n 
LEFT JOIN Organizers co ON n.cid = co.cid 
LEFT JOIN Participants cp ON n.cid = cp.cid 
GROUP BY n.cid