Question

嘿所以我正在编制一个程序来计算到目前为止我的程序的能源成本，但我希望所有三个设备的瓦特小时数不仅仅是一个我怎么做？：

#include <iostream>
using namespace std;

int main ()
{
   double watts, hours_per_day, watt_hours, dollars_per_wh;

   dollars_per_wh= .00008;

   cout << " How many Watts for the Air conditioner? ";
   cin >> watts;
   cout << " How many hours/day do you run the Air Conditioner? ";
   cin >> hours_per_day;


   cout << "How many Watts for the Television? " ;
   cin >> watts;
   cout << "How many hours/day do you run the Television? " ;
   cin >> hours_per_day;


   cout << "How many Watts for the Washer? " ;
   cin >> watts;
   cout << "How many hours/day do you run the Washer? " ;
   cin >> hours_per_day;

   watt_hours = watts * hours_per_day * 30;
   cout << "You have used " << watt_hours << " Watts-Hours of electricity." << endl;

Answer 1

您必须为每个设备使用独立的watts变量和hours_per_day。

考虑使用循环来实现这一点，它会使代码更清晰，尺寸更小;

#include <iostream>
#include <string>
#include <vector>

using std::cout;
using std::cin;
using std::endl;

static const double dollars_per_wh = 0.00008;

int main(int argc, char ** argv)
{
    int num_apps = 3;
    std::vector<std::string> v_apps;
    v_apps.push_back("Air conditioner");
    v_apps.push_back("Television");
    v_apps.push_back("Washer");

    double watt, hours, watt_hours = 0;
    for(register int i = 0; i < num_apps; ++i)
    {
        cout << "How many watts for the " << v_apps[i].c_str() << "? ";
        cin >> watt;
        cout << "How many hours/day do you run the " << v_apps[i].c_str() << "? ";
        cin >> hours;
        watt_hours = watt_hours + ((watt * hours) * 30);
    }
    cout << "You have used " << watt_hours << " Watt-Hours of electricity." << endl;
    return 0;
}

Answer 2

我猜你可以用三重变量做以下事情：

#include <iostream>
using namespace std;

int main ()
{
   double watts_ac, watts_tv, watts_wa;
   double hours_per_day_ac, hours_per_day_tv, hours_per_day_wa;
   double watt_hours, dollars_per_wh;

   dollars_per_wh= .00008;

   cout << " How many Watts for the Air conditioner? ";
   cin >> watts_ac;
   cout << " How many hours/day do you run the Air Conditioner? ";
   cin >> hours_per_day_ac;


   cout << "How many Watts for the Television? " ;
   cin >> watts_tv;
   cout << "How many hours/day do you run the Television? " ;
   cin >> hours_per_day_tv;


   cout << "How many Watts for the Washer? " ;
   cin >> watts_wa;
   cout << "How many hours/day do you run the Washer? " ;
   cin >> hours_per_day_wa;

   watt_hours = (watts_ac * hours_per_day_ac + watts_tv * hours_per_day_tv + watts_wa * hours_per_day_wa) * 30; //I'm not sure what this 30 factor is due to though.
   cout << "You have used " << watt_hours << " Watts-Hours of electricity." << endl;
}

或只汇总数据：

#include <iostream>
using namespace std;

int main ()
{
   double watts, hours_per_day_ac, watt_hours, dollars_per_wh;

   dollars_per_wh= .00008;

   cout << " How many Watts for the Air conditioner? ";
   cin >> watts;
   cout << " How many hours/day do you run the Air Conditioner? ";
   cin >> hours_per_day;
   watts_hours = watts*hours_per_day;


   cout << "How many Watts for the Television? " ;
   cin >> watts;
   cout << "How many hours/day do you run the Television? " ;
   cin >> hours_per_day;
   watts_hours += watts*hours_per_day;


   cout << "How many Watts for the Washer? " ;
   cin >> watts;
   cout << "How many hours/day do you run the Washer? " ;
   cin >> hours_per_day;
   watts_hours += watts*hours_per_day;

   watt_hours *= 30; //I'm not sure what this 30 factor is due to though.
   cout << "You have used " << watt_hours << " Watts-Hours of electricity." << endl;
}

关于添加三个变量C ++的问题

2 个答案: