如何在unix中的echo中显示单引号和双引号

Question

我需要在unix中显示类似今天＆＃34;程序＆＃34; 的字符串作为输出。但是，如果我给出以下没有选项正在运作。

>echo "Today's "program""
Today's program

> echo "Today\'s "program""
Today\'s program

> echo 'Today's "program"'
>

echo 'Today\'s "program"'
>

Answer 1

如果要在双引号内显示​​双引号，则必须转义它们：

$> echo "today's \"program\""
today's "program"

您还可以连接引用的字符串：

$> echo 'today'"'"'s "program"'
today's "program"

或者只是逃避它们：

$> echo today\'s \"program\"
today's "program"

Answer 2

> echo 'Today'\''s "program"'
Today's "program"

Answer 3

多种可能性：

> echo 'Today'"'"'s "program"'
Today's "program"
> echo Today"'"s '"program"'
Today's "program"
> echo Today\'s '"program"'
Today's "program"
> echo Today\'s \"program\"
Today's "program"

有关这三种逃避的区别，请参阅this article。