Question

我有一个包含以下数据的文本文件：温兆伦，罗伯特，马修，

现在，我希望用户输入一个字符串，然后将该字符串与文本文件进行比较..

 fo = open("d:\\ar.txt", "r")
 file_contents = fo.read()
 print('Enter your password.')
 typedPassword = input()
 for i in file_contents:
     if typedPassword == file_contents:
         print('Access granted')
     else:
         print('Access denied')

但是，这似乎不起作用。有什么想法吗？

Answer 1

试试这个： -

fo = open("poopy.txt", "r")
file_contents = fo.read()
print('Enter your password.')
typedPassword = input()
Flag = 0
for i in file_contents.split('\n'):
    if typedPassword == i:
        Flag = 1
if Flag == 1:
    print('Access Granted')
else:
    print('Access Denied')

Answer 2

您正在检查输入的密码是否与整个文件匹配... 这会检查每一行

username = input("Input your username")
password = input("Input your password")
correct = None
with open("d:\\ar.txt", "r") as file:
    for line in file:
        line = line.split(",")
        if username == line[0] and password == line[1]:
            correct = True
if correct:
    print("") # placeholder
    #(logged in code)

为此工作你的文件应该是fornat

用户名，密码，

将python中的字符串与文本文件进行比较

2 个答案: